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11Alexandr11 [23.1K]
3 years ago
13

Germanium has a face-centered cubic unit cell. The density of germanium is 5.32 g/cm3. Calculate a value for the atomic radius o

f germanium.
Chemistry
1 answer:
Cloud [144]3 years ago
7 0

Answer:

1.59x10⁻¹⁰m

Explanation:

To solve this question we must know that the length of the cubic cell, X, is equal to:

X = √8 * R

<em>Where R is the atomic radius of germanium</em>

And that in 1 unit cell there are 4 atoms of germanium.

To solve this question we must find the mass in 1 unit cell, with this mass we can find the volume of the cube and the length. With the length we can know the atomic radius:

<em>Mass in 1 unit cell -Molar mass Ge = 72.64g/mol:</em>

4 atoms Ge * (1mol / 6.022x10²³ atoms) = 6.64x10⁻²⁴ moles Ge

6.64x10⁻²⁴ moles Ge * (72.64g / mol) = 4.825x10⁻²²g Ge

<em>Volume unit cell:</em>

4.825x10⁻²²g Ge * (1cm³ / 5.32g) = 9.07x10⁻²³cm³

<em>Length unit cell:</em>

∛9.07x10⁻²³cm³ = 4.49x10⁻⁸cm * (1m / 100cm) = 4.49x10⁻¹⁰m

<em>Atomic radius Ge:</em>

4.49x10⁻¹⁰m / √8 =

<h3>1.59x10⁻¹⁰m</h3>
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