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Alexxandr [17]
3 years ago
7

The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal

lel to a uniform magnetic field of 50.0 T in which it lies. Question 5. The magnitude and direction of the total magnetic moment is ……to the area vector.
Physics
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

M= 0.4 Am^2

Explanation:

From the question we are told that:

Number of turns  N=5N=5

Conductor each with side length L=0.2m

Current I=2A

Magnetic field  B=50.0T

Generally the equation for the total magnetic moment  M is mathematically given by

M = current * area

M= I * A

M = 2 * (5* 0.2*0.2)  

M = 2 * 0.2

M= 0.4 Am^2

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