Answer:
hello your question is incomplete attached below is the complete question
answer :
a) I1 = I2
b) J1 > J2
c) E 1 > E2
d) ( vd1 ) > ( vd2 )
Explanation:
a) The currents in the two segments are the same i.e. I1 = I2 and this is because the segments are connected in series
b) Comparing the current densities J1 and J2 in the two segments
note : current density ∝ 1 / area
The area of the second segment is > the area of first segment therefore
J1 > J2
J1 ( current density of first segment )
J2 ( current density of second segment )
c) Comparing the electric field strengths E1 and E2
note : electric field strength ∝ current density
since current density of first segment is > current density of second segment and conductivity of the materials are the same hence
E 1 > E2
d) Comparing the drift speeds Vd1 and Vd2
( vd1 ) > ( vd2 )
this because ; vd ∝ current density
Answer:
4 N to the right
Explanation:
For the object in this problem, we have 2 forces acting on it:
- A force of 2 N, to the right
- A force of 2 N, to the right
The two forces are in line: this means that the two vectors can be simply added by calculating their algebraic sum.
If we take right as positive direction, the two forces can be written as
F1 = +2 N
F2 = +2 N
So, the net force will be
And the positive sign means the direction is to the right.
Explanation:
It is given that,
Diameter of the peach pie, d = 9 inches
Radius of the pie, r = 4.5 inches
The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches
Let is the angular distance that the pie plate has moved through.
It is given by :
Since, 1 radian = 57.29 degrees
Since, 1 radian = 0.159155 revolution
Hence, this is the required solution.