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Anvisha [2.4K]
2 years ago
11

Please help, AND READ DIRECTIONS, get done as soon as possible.

Mathematics
1 answer:
katen-ka-za [31]2 years ago
7 0

Answer:

IT would be 13a to 17b

Step-by-step explanation:

I had this.

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Equivalent equation for 4^2 =16
mihalych1998 [28]
Hello there!


To do this, we will take the square root from each side

4^2 would be 4

16 would be 4

4 = 4


I hope I helped!

~ Fire
7 0
3 years ago
Find the quotient. (12x 2 - 10x -12) ÷ (3x + 2)
MAXImum [283]
I'm attaching the solution.. feel free to ask if you have questions.. I basically did long division.  Hope this helps.

5 0
2 years ago
Sub to bionic pleasssssse
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4 0
3 years ago
Read 2 more answers
F(x)=9x^2 <br><br> g(x)= sqrt 12-x/3<br><br> (f o g)(-4)
Slav-nsk [51]

f(x)=9x^2 \\ g(x)=\frac{\sqrt{12-x}}{3} \\ So,first step is to write (fog)(-4)) =f[g(-4)] \\

Now we start from inner paranthesis ,we need to first find value of g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\&#10;=\frac{\sqrt{16}}{3}\\&#10;=\frac{4}{3}\\&#10;(fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16     

8 0
3 years ago
Expres each of the folowing as a single matrix.
Elden [556K]

Answer:

\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]

Step-by-step explanation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]

We have:

A=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]\\and\\B=\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]

And we need to express as a single matrix:

A+B=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6+(-2)&-3+8\\10+3&-1+(-12)\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6-2&5\\13&-1-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]

The answer is:

\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]

It is expressed as a single matrix.

8 0
3 years ago
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