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Delicious77 [7]
3 years ago
9

In the national grid,what does the step up transformer do?

Physics
2 answers:
diamong [38]3 years ago
8 0
The power that's lost when current flows through anything is

       (current)² times (resistance).

You can see that in order to minimize the power lost in transporting electrical
energy from one place to another, you'd want to make both the resistance of
the conductors and the current through the lines as low as possible.

The resistance is reduced by using heavier (fatter) conductors, and using
as much silver or copper in them as possible ... both very expensive.

Power = (current) times (voltage), so the way to reduce the current while
shipping the same power from place to place is to increase the voltage. 
That's exactly what the transformer does ... it changes the voltage and
current, while keeping their product the same.  It's used to step the voltage
up for transmission, in several steps from the generating station all the way
to the residential neighborhood, and then finally back down, on the pole
near your house.
amm18123 years ago
7 0
In the National Grid, the Step Up Transformer increases the amount of voltage that is passing through the grid at any one time. These are used at power stations, as without them, there would not be enough power to transport the electricity around the national grid.
Hope this helps :) 
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Ket [755]

c it is both a and b

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3 years ago
What is a tool that measures the size of a force
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3 years ago
Light of wavelength 630 nm is incident on a long, narrow slit. Determine the angular deflection of the first diffraction minimum
asambeis [7]

Answer:

a) 1.8°

b) 0.18°

c) 0.018°

Explanation:

Wavelength (λ) = 630nm = 630 *10^-9m

The equation that describes the angular deflection of a dark band is

Wsin(βm) = mλ

w = width of the single slit

λ = wavelength of the light

βm = angular deflection of the mth dark band.

a) In order to get the angular deflection of the first dark band for a slit with 0.02mm width, substitute w = 0.02mm = 0.02*10^-3 , m = 1 , λ= 630*10^-9

0.02*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.02*10^-3

Sin(β1) = 0.0315

β1 = Sin^-1(0.0315)

= 1.8°

b) substitute w = 0.2mm = 0.2*10^-3 , m = 1 , λ= 630*10^-9

0.2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.2*10^-3

Sin(β1) = 0.00315

β1 = Sin^-1(0.00315)

= 0.18°

c) substitute w = 2mm = 2*10^-3 , m = 1 , λ= 630*10^-9

2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 2*10^-3

Sin(β1) = 3.15*10^-4

β1 = Sin^-1(3.15*10^-4)

= 0.018°

6 0
3 years ago
A train travels 90 kilometers in 2 hours, and then 66 kilometers in 2 hours. What is its average speed?
Inessa05 [86]
90+66=156
156/2=78

Reply:78kilometers in 2 hours.
3 0
3 years ago
There are two parts, answer both, please dont just say part 1 is the correct answer
nordsb [41]

Answer:

Im not sure

Explanation:

4 0
3 years ago
Read 2 more answers
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