Answer:
The balloon would still move like a rocket
Explanation:
The principle of work of this system is the Newton's third law of motion, which states that:
"When an object A exerts a force on an object B (action), object B exerts an equal and opposite force (reaction) on object A"
In this problem, we can identify the balloon as object A and the air inside the balloon as object B. As the air goes out from the balloon, the balloon exerts a force (backward) on the air, and as a result of Newton's 3rd law, the air exerts an equal and opposite force (forward) on the balloon, making it moving forward.
This mechanism is not affected by the presence or absence of surrounding air: in fact, this mechanism also works in free space, where there is no air (and in fact, rockets also moves in space using this system, despite the absence of air).
The air pressure is most likely lower.
Answer:
Explanation:
As we know,
=》Force = Mass × Acceleration
=》45 N = 0.75 × Acceleration
=》Acceleration = 45 ÷ 0.75
=》Acceleration = 60
hence, the Acceleration of the ball would be. 60 meters per second square
Resistance = (voltage) / (current)
Resistance = (100 V) / (20 A)
<em>Resistance = 5 Ω (D)</em>
The answer would be no. Both will have same charge, in both caes charge will reside on surface. In case of solid sphere it will be distributed evenly throughout. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
