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8090 [49]
3 years ago
14

In general, the greatest variation happens in populations of organisms that reproduce_____.

Chemistry
1 answer:
insens350 [35]3 years ago
8 0

Explanation:

A.) Asexually would be the correct answer!

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The value of the equilibrium constant for the combination of nitrogen and oxygen to make NO is 2 x 10-9. What does this tell you
Rama09 [41]

Answer:

A

Explanation:

A

7 0
3 years ago
How would one convert 125 lb to kilograms (1 oz = 28 g)?
scZoUnD [109]

Answer:

these answer choices are extremely confusing to read lol.

so the answer is 125lb x 16oz/1lb x 28g/1oz x 1kg/1000g

<em>a p e x</em>

6 0
3 years ago
A researcher discovers a new bacterium that lives on the seafloor near hydrothermal vents. This organism reduces CO2 to form C6H
KonstantinChe [14]

Answer:

C. Chemoautotroph

Explanation:

The new bacterium are able to create their own energy and biological materials  (glucose) from inorganic chemicals (CO2 and H2), therefore they are called chemoautotroph.

5 0
3 years ago
An undergraduate weighed out 20grams of sodium hydroxide pellets. If Na =23, O = 16 andH = 1, What is the mole of this sodium hy
tatuchka [14]
The answer would be .5 mols because you take the total amount of grams, which is 20, and you had up the molar mass of sodium hydroxide, which would be 40. After you have this you would set this up as a stochiometry equation. With 1 mol on top you dived 20/40 to cancel out your grams. This leaves you with .5 mols

3 0
3 years ago
which atom has a change in oxidation number of -3 in the following redox reaction K2Cr2O7 + H2O +S --&gt; KOH + Cr2O3 +SO2
yaroslaw [1]
You have to calculate the oxidation estates of the atoms in each compound.

I will start with K2Cr2O7 because I believe that Cr is the best candidate to reduce its oxidation number in 3 units.

In K2Cr2O7:

- K has oxidation state of 1+, then K2 has a charge of 2* (1+) = 2+.

- O has oxidation state of 2*, then O7 has a charge of 7* (2-) = 14-.

That makes that Cr2 has charge of 14 - 2 = +12, so each Cr has +12/2 = +6 oxidation state.

In Cr2O3:

- O has oxidation state of 2-, then O3 has charge 3 * (2-) = - 6

- Then, Cr2 has charge 6+, and each Cr has charge 6+ / 2 = 3+.

So, we have seen that Cr reduced its oxidation state in 3 units, from 6+ to 3+.

Answer: Cr has a change in oxidation number of - 3.
6 0
3 years ago
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