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Anika [276]
2 years ago
8

Help please!!! Don't come and steal my points please, I really need this answered.

Mathematics
2 answers:
zhenek [66]2 years ago
8 0

Answer: 4x \leq 36

Step-by-step explanation: Four times the number is no more than ("less than or equal to") 36:   4x ≤ 36  (by dividing both sides by 4, this is equivalent to  x ≤ 9 )

Hope this helped!!!!!!!!!! And ps why are there so many people stealing points on here now

neonofarm [45]2 years ago
6 0
C because it says no more not equal too
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What is the answer to this? It says I have to factor it
Aleksandr [31]
(x-4)(x+9) because X to the power of 2 +9x+(-4x)-36 =(x-4)(x+9)
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The product of two consecutive numbers is 4 more than three times the larger. find the integer​
Stella [2.4K]

Answer:

Step-by-step explanation:

Let the first integer be x, then the next is x+1.

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2 years ago
Given the function () = $
elena-s [515]

The inverse of the function f(x) = 1/3x^2 - 3x + 5 is  f-1(x) = 9/2 + √[3(x + 7/4)], the sum of the arithmetic series is 1078 and the common ratio of the sequence is 2

<h3>The inverse of the function?</h3>

The function is given as:

f(x) = 1/3x^2 - 3x + 5

Next, we rewrite the function as in vertex form

Using a graphing calculator, the vertex form of the function f(x) = 1/3x^2 - 3x + 5 is

f(x) = 1/3(x - 9/2)^2 - 7/4

Express f(x) as y

y = 1/3(x - 9/2)^2 - 7/4


Swap x and y

x = 1/3(y - 9/2)^2 - 7/4

Add 7/4 to both sides

1/3(y - 9/2)^2 = x + 7/4

Multiply through  by 3

(y - 9/2)^2 = 3(x + 7/4)

Take the square root of both sides

y - 9/2 = √[3(x + 7/4)]

Add 9/2 to both sides

y = 9/2 + √[3(x + 7/4)]

Rewrite as an inverse function

f-1(x) = 9/2 + √[3(x + 7/4)]

<h3>Sum of arithmetic series</h3>

Here, we have:

5 + 18 + 31 + 44 + ... 161

Calculate the number of terms using:

L = a + (n -1)d

So, we have:

161 = 5 + (n - 1) * 13

This gives

(n - 1) * 13 = 156

Divide by 13

n - 1 = 12

Add 1

n = 13

The sum is then calculated as:

Sn = n/2 * [a + L]

This gives

Sn =13/2 * (5 + 161)

Evaluate

Sn = 1078

Hence, the sum of the arithmetic series is 1078

<h3>The common ratio of the sequence</h3>

Here, we have:

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This gives

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Divide by ar^5

r^5 = 32

Take the fifth root

r = 2

Hence, the common ratio of the sequence is 2


Read more about sequence at:

brainly.com/question/7882626

#SPJ1

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