Answer:
9.1 mol
Explanation:
The balanced chemical equation of the reaction is:
CO (g) + 2H2 (g) → CH3OH (l)
According to the above balanced equation, 2 moles of hydrogen gas (H2) are needed to produce 1 mole of methanol (CH3OH).
To convert 36.7 g of hydrogen gas to moles, we use the formula;
mole = mass/molar mass
Molar mass of H2 = 2.02g/mol
mole = 36.7/2.02
mole = 18.17mol
This means that if;
2 moles of H2 reacts to produce 1 mole of CH3OH
18.17mol of H2 will react to produce;
18.17 × 1 / 2
= 18.17/2
= 9.085
Approximately to 1 d.p = 9.1 mol of methanol (CH3OH).
The wheels will be completely used up and it is the limiting reactant in this case.
<h3>What is a limiting reactant?</h3>
The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.
- 60 breaks will be used for 30 engines and 30 body frame
- 80 wheels will be used for 20 engines and 20 body frame
- 64 headlights will be used for 32 engines and 32 body frame
The wheels will be completely used up and it is the limiting reactant in this case.
Learn more about limiting reactants here: brainly.com/question/14222359
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Answer:
Option 1
Explanation:
Option number 1 is the most compact one which indicates it is a solid
Answer:
1120 gm
Explanation:
6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)
(a) Balance the equation.
(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete
combustion reaction?
FIRST, CORRECT THE EQUATION THEN BALANCE
2C2H6(G) + 7O2------------> 4CO2 + 6H2O
so for 10 moles of ethane, we need
7 X 5 = 35 MOLES O2
=35 MOLES O2
O2 HAS A MOLAR MASS OF 2X16 = 32 gm
35 MOLES OF O2 HAS A MASS OF 35 X 32 =1120 gm
The potential energy of the products is higher than the potential energy of the reactants.
