A system does 591 kJ of work and loses 256 kJ of heat to the surroundings.
1 answer:
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Answer:
The mean free path = 2.16*10^-6 m
Explanation:
<u>Given:</u>
Pressure of gas P = 100 kPa
Temperature T = 300 K
collision cross section, σ = 2.0*10^-20 m2
Boltzmann constant, k = 1.38*10^-23 J/K
<u>To determine:</u>
The mean free path, λ
<u>Calculation:</u>
The mean free path is related to the collision cross section by the following equation:
where n = number density
Substituting for P, k and T in equation (2) gives:
Next, substituting for n and σ in equation (1) gives:
0.72 mole of oxygen would produce 320.4 kJ of heat.
<u>Explanation:</u>
CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (ℓ) + 890kJ
According to the equation,
2 moles of O₂ produces 890 kJ of heat
So, 0.72 moles of O₂ will produce:
Therefore, 0.72 mole of oxygen would produce 320.4 kJ of heat.