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Jlenok [28]
3 years ago
15

Identify the type of weathering seen in each picture

Physics
2 answers:
stiks02 [169]3 years ago
7 0

Answer:

If this is the question I think it is, the answer is;

mechanical, chemical, chemical, mechanical

There's no picture so I can't tell though

Explanation:

alukav5142 [94]3 years ago
5 0
Where is the picture
?
You might be interested in
Can someone help with numbers 5-8??
Keith_Richards [23]

5. Left

Explanation: centripetal acceleration is the acceleration that acts on an object which is moving by circular motion. The direction of the centripetal acceleration is always towards the centre of the circular trajectory: that means that for a car following a bend, the direction of the centripetal acceleration is towards the centre of the bend, and so it is towards the left if the bend is towards the left, and towards the right if the bend is towards the right.

In this example, the road in this bend is going to the left, so centripetal acceleration is toward the left as well.


6. Greater

Explanation: Inertia represents the tendency of an object at staying in motion if it is moving, and at staying at rest if the object is at rest. We can also see inertia as a measure of "how difficult it is" to put an object in motion. Due to this definition, we can also notice that inertia is directly proportional to the mass of the object: the greater the mass, the greater the inertia, because it is more difficult to put the object in motion.

So, in this example, the greater the boulder's mass, the greater inertia it has.


7. Direction

Explanation: displacement is a vector quantity that represents the difference in position between an object and a starting point. Because it is a vector, displacement consists of two elements:

- A magnitude, which is equal to the object's distance from the starting point

- A direction, again compared to the starting point

So, displacement depends on the object's distance and direction from the starting point.


8. Negative

Explanation: acceleration is defined as the rate of change of velocity; in formula:

a=\frac{v-u}{t}

where v is the final velocity, u the initial velocity, and t the time taken to accelerate from u to v. From the formula, we see that:

- When the final velocity (v) is greater than the initial velocity (u), acceleration is positive

- When the final velocity (v) is smaller than the initial velocity (u), acceleration is negative

In this problem, we have a car slowing down: it means that the final velocity is smaller than the initial velocity, so in this case acceleration is negative.

7 0
3 years ago
A) How much does an 85g apple weight on the surface of the Earth? (gEarth = 9.8 m/s2)
liq [111]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em>

4 0
3 years ago
Energy Conservation With Conservative Forces: If a spring-operated gun can shoot a pellet to a maximum height of 100 m on Earth,
crimeas [40]

Answer:

h' = 603.08 m

Explanation:

First, we will calculate the initial velocity of the pellet on the surface of Earth by using third equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity on the surface of earth = - 9.8 m/s² (negative sign due to upward motion)

h = height of pellet = 100 m

Vf = final velocity of pellet = 0 m/s (since, pellet will momentarily stop at highest point)

Vi = Initial Velocity of Pellet = ?

Therefore,

(2)(-9.8 m/s²)(100 m) = (0 m/s)² - Vi²

Vi = √(1960 m²/s²)

Vi = 44.27 m/s

Now, we use this equation at the surface of moon with same initial velocity:

2g'h' = Vf² - Vi²

where,

g' = acceleration due to gravity on the surface of moon = 1.625 m/s²

h' = maximum height gained by pellet on moon = ?

Therefore,

2(1.625 m/s²)h' = (44.27 m/s)² - (0 m/s)²

h' = (1960 m²/s²)/(3.25 m/s²)

<u>h' = 603.08 m</u>

4 0
3 years ago
P6: An object of mass m sits on a spring of constant k in an elevator that is accelerating upwards with acceleration a. a) In te
tankabanditka [31]

Answer:

(a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

Explanation:

Given that,

Acceleration = a

mass = m

spring constant = k

(a). We need to calculate the spring compressed

Using balance equation

kx-mg=ma

x=\dfrac{ma+mg}{k}....(I)

The spring compressed is \dfrac{ma+mg}{k}.

(b). If the compression is 2.5 times larger than it is when the mass sits in a still elevator,

The compression is given by

x=2.5\times x_{0}

Here, acceleration is zero

So, x=2.5\times\dfrac{mg}{k}

We need to calculate the acceleration

Put the value of x in equation (I)

2.5\times \dfrac{mg}{k}=\dfrac{ma+mg}{k}

2.5\times\dfrac{mg}{k}=\dfrac{m}{k}(a+g)

a=2.5g-g

a=1.5g

Hence, (a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

8 0
3 years ago
At the end of a race a runner decelerates from a velocity of 8.90 m/s at a rate of 1.70 m/s2. (a) How far in meters does she tra
Ad libitum [116K]

Answer:

x=22.33m

Explanation:

Kinematics equation for constant deceleration:

x =v_{o}*t - 1/2*at^{2}=8.9*6.3-1/2*1.70*6.3^{2}=22.33m

7 0
3 years ago
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