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How can I find the quotient of 27 divided 91.8

gayaneshka [121]

Step 1:
Start by setting it up with the divisor 8 on the left side and the dividend 27 on the right side like this:

8 ⟌ 2 7

Step 2:
The divisor (8) goes into the first digit of the dividend (2), 0 time(s). Therefore, put 0 on top:

0
8 ⟌ 2 7

Step 3:
Multiply the divisor by the result in the previous step (8 x 0 = 0) and write that answer below the dividend.

0
8 ⟌ 2 7
0

Step 4:
Subtract the result in the previous step from the first digit of the dividend (2 - 0 = 2) and write the answer below.

0
8 ⟌ 2 7
- 0
2

Step 5:
Move down the 2nd digit of the dividend (7) like this:

0
8 ⟌ 2 7
- 0
2 7

Step 6:
The divisor (8) goes into the bottom number (27), 3 time(s). Therefore, put 3 on top:

0 3
8 ⟌ 2 7
- 0
2 7

Step 7:
Multiply the divisor by the result in the previous step (8 x 3 = 24) and write that answer at the bottom:

0 3
8 ⟌ 2 7
- 0
2 7
2 4

Step 8:
Subtract the result in the previous step from the number written above it. (27 - 24 = 3) and write the answer at the bottom.

0 3
8 ⟌ 2 7
- 0
2 7
- 2 4
3

You are done, because there are no more digits to move down from the dividend.

The answer is the top number and the remainder is the bottom number.

Therefore, the answer to 27 divided by 8 calculated using Long Division is:

3

8 0

3 years ago

Think for a moment about the potential problems with big data that the speaker mentioned:

Natalka [10]

Answer: 1. sadly yes, some people are treated unfairly for crimes people yet have commited. 2. no 3. yes

Explanation:

i did this last year

5 0

3 years ago

Read 2 more answers

You are an engineer in an electric-generation station. You know that the flames in the boiler reach a temperature of 1200 K and

olga nikolaevna [1]

Answer:

The maximum efficiency the plant will ever achieve is 75%

Explanation:

From the question given, we recall the following:

Th flames in the boiler reaches a temperature of = 1200K

the cooling water is = 300K

The maximum efficiency the plant will achieve is defined as:

Let nmax = 1 - Tmin /Tmax

Where,

Tmin = Minimum Temperature in plants

Tmax = Maximum Temperature in plants

The temperature of the cooling water = Tmin = 300K

The temperature of the flames in boiler = Tmax = 1200k=K

The maximum efficiency becomes:

nmax = 1 - Tmin /Tmax

nmax = 1 - 300 /1200

nmax = 1-1/4 =0.75

nmax = 75%

5 0

4 years ago

Para uma dada velocidade do vento, o gerador de turbina mostrado na figura produz 22 kW de potência elétrica. Como um sistema co

____ [38]

Answer:

b

Explanation:

4 0

3 years ago

Consider a voltage v = Vdc + vac where Vdc = a constant and the average value of vac = 0. Apply the integral definition of RMS t

Anna11 [10]

Answer:

Proof is as follows

Proof:

Given that , $V = V_{ac} + V_{dc}$

for any function f with period T, RMS is given by

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[f(t)]^{2} } \, dt }$

In our case, function is $V = V_{ac} + V_{dc}$

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac} + V_{dc}]^{2} } \, dt }$

Now open the square term as follows

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac}^{2} + V_{dc}^{2} + 2V_{dc}V_{ac}] } \, dt }$

Rearranging terms

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {V_{dc}^{2} } \, dt + \frac{1}{T}\int\limits^T_0 {V_{ac}^{2} } \, dt + \frac{1}{T}\int\limits^T_0 {2V_{dc}V_{ac} } \, dt }$