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2 years ago

What is the role of the architects in modern development

Engineering

1 answer:

pshichka [43]2 years ago

7 0

Answer:

to plan, design, and oversee the construction of a building

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The federal highway administration reports nearly

levacccp [35]

Explanation:

The federal highway administration reports nearly 800 work zone fatalities per year.

8 0

3 years ago

A 10 wt % aqueous solution of sodium chloride is fed to an evaporative crystallizer which operates at 80o C. The product is a sl

VikaD [51]

Answer: The feed rate is

17,020kg/he and the rate is 13,520kg/h

Check the attachment for step by step explanation

3 0

3 years ago

water flows in a horizontal constant-area pipe; the pipe diameter is 75 mm and the average flow speed is 5 m/s. At the pipe inle

Veronika [31]

Answer:

Head loss = 28.03 m

Explanation:

According to Bernoulli's theorem for fluids we have

$\frac{P}{\gamma _{w}}+\frac{V^{2}}{2g}+z=Constant$

Applying this between the 2 given points we have

$\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}=\frac{P_{2}}{\gamma _{w}}+\frac{V_{2}^{2}}{2g}+z_{2}+h_{l}$

Here $h_{l}$ is the head loss that occurs

$\therefore h_{l}=\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}-\frac{P_{2}}{\gamma _{w}}-\frac{V_{2}^{2}}{2g}-z_{2}$

Since the pipe is horizantal we have $z_{1}-z_{2}=0$

Applying contunity equation between the 2 sections we get

$A_{1}V_{1}=A_{2}V_{2}\\\\\therefore V_{1}=V_{2}(\because A_{1}=A_{2})$

Since the cross sectional area of the both the sections is same thus the speed

is also same

Using this information in the above equation of head loss we obtain

$h_{l}=\frac{1}{\gamma _{w}}(P_{1}-P_{2})$

Applying values we get

$h_{l}=\frac{1}{9810}\times (275\times 10^{3})m\\\\\therefore h_{l}=28.03m$

3 0

3 years ago

If _____, use threshold braking any time you need to brake hard.

Vaselesa [24]

Answer:

You don’t have ABS

8 0

3 years ago

Read 2 more answers

Evaluate (204 mm)(0.004 57 kg) / (34.6 N) to three

vesna_86 [32]

Answer:

the evaluation in SI unit will be $2.69\times 10^{-5}sec^{2}$

Explanation:

We have evaluate $\frac{(204mm\times 0.00457kg)}{34.6N}$

We know that 1 mm $=10^{-3}m$

So 240 mm $=204\times 10^{-3}m$

Newton can be written as $kgm/sec^2$

So $\frac{(204\times 10^{-3}m)\times 0.00457kg}{34.6kgm/sec^2}=2.69\times 10^{-5}sec^{2}$

So the evaluation in SI unit will be $2.69\times 10^{-5}sec^{2}$

4 0

3 years ago

What is the role of the architects in modern development​

What is the role of the architects in modern development