Answer:
A) EXIT TEMPERATURE = 14⁰C
b) rate of heat transfer of air = - 13475.78 = - 13.5 kw
Explanation:
Given data :
diameter of duct = 20-cm = 0.2 m
length of duct = 12-m
temperature of air at inlet= 50⁰c
pressure = 1 atm
mean velocity = 7 m/s
average heat transfer coefficient = 85 w/m^2⁰c
water temperature = 5⁰c
surface temperature ( Ts) = 5⁰c
properties of air at 50⁰c and at 1 atm
= 1.092 kg/m^3
Cp = 1007 j/kg⁰c
k = 0.02735 W/m⁰c
Pr = 0.7228
v = 1.798 * 10^-5 m^2/s
determine the exit temperature of air and the rate of heat transfer
attached below is the detailed solution
Calculate the mass flow rate
= p*Ac*Vmean
= 1.092 * 0.0314 * 7 = 0.24 kg/s
Answer:
mwuah
Explanation:
I got u girl, what r u on?
The answer is because the positive goes with the positive
Answer:
Explanation:
Simply put, a solar panel works by allowing photons, or particles of light, to knock electrons free from atoms, generating a flow of electricity. Solar panels actually comprise many, smaller units called photovoltaic cells. (Photovoltaic simply means they convert sunlight into electricity. The attached diagram give an ilustsration of the photovotaic pannel mounted on a roof top.
Solution
To Determine the electric power generated for
a) A still summer day.
E = A * r * H * PR
E = Total Amount of Energy in kilowatt
A = Total Surface Area
r = efficiency Rating
H = global radiation value
PR = Performance Ratio
kwh = watt * Time/1000
kwh = 100 * 35/1000
3.5
b)
kwh = watt * Time/1000
kwh = 30 *15/1000
4.5
Answer:
2200 W
Explanation:
Use the given relation between current, voltage, and power to find the power requirement:
P = IV
P = (20 A)(110 V) = 2200 W
