3 years ago

How much does a 60 kg table weigh

Physics

1 answer:

soldier1979 [14.2K]3 years ago

5 0

Answer:

588 N

Explanation:

weigh = Mg

I hope you got that. Thanks and upovote that

You might be interested in

Which of the following best summarizes the quantum model of atoms?

Lelechka [254]

I believe it is A. Electrons reside in known positions in fixed orbits around the nucleus

6 0

3 years ago

Which tool would you use to measure the amount of rainfall?

zheka24 [161]

Answer:

Explanation:

5 0

3 years ago

Read 2 more answers

What type of objects cannot pull to magmets

boyakko [2]

Answer:

brass, copper, zinc and aluminum, wood, glass, and plastic

Explanation:

7 0

3 years ago

Read 2 more answers

Given the initial wavefunction Ψ (x, 0) = Axexp (-k x) withx> 0 andk> 0, and Ψ (x, 0) = 0 forx <0, what value must A ta

madam [21]

Answer with explanation:

The Normalization Principle states that

$\int_{-\infty }^{+\infty }f(x)dx=1$

Given

$f(x)=xe^{-kx}(x>0\\\\0(x$

Thus solving the integral we get

$\int_{0 }^{+\infty }A\cdot xe^{-kx}dx=1\\\\A\int_{0 }^{+\infty }\cdot xe^{-kx}dx=1$

The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below

$I=\int xe^{-kx}dx\\\\x\int e^{-kx}dx-\int \frac{d(x)}{dx}\int e^{-kx}dx\\\\-\frac{xe^{-kx}}{k}-\int 1\cdot \frac{-e^{-kx}}{k}\\\\\therefore I=\frac{e^{-kx}}{k}-\frac{xe^{-kx}}{k}$

Applying the limits and solving for A we get

$I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k$

3 0

3 years ago

If a truck driver is driving at 30 mph and she makes a U-turn, then starts driving at 30 mph in the opposite direction, did the

AlekseyPX

Answer:

i dont mow

Explanation:

6 0

3 years ago