Light is a very complex phenomenon, but in many situations its behavior can be understood with a simple model based on rays and wave fronts. A ray is a thin beam of light that travels in a straight line. A wave front is the line (not necessarily straight) or surface connecting all the light that left a source at the same time. For a source like the Sun, rays radiate out in all directions; the wave fronts are spheres centered on the Sun. If the source is a long way away, the wave fronts can be treated as parallel lines.
Rays and wave fronts can generally be used to represent light when the light is interacting with objects that are much larger than the wavelength of light, which is about 500 nm. In particular, we'll use rays and wave fronts to analyze how light interacts with mirrors and lenses.
Answer:
2023857702.507m
Explanation:
recall from newton's law of gravitation
G=gravitational constant
mshew=50g
melephant=5*10^3kg
rearth=radius of the earth 6400km or 6400000m
mearth= masss of the earth
Gm(shrew)m(earth)/r(earth)^2 = Gm(elephant)m(earth)/r^2
strike out the left hand side and right hand side variables
m(shrew)/r(earth)^2 = m(elephant)/r^2
r^2 = m(elephant).r(earth)^2 / m(shrew) .........make r^2 the subject of the equation
r^2=
r^2=40960000000000
r=2023857702.507m
Answer:
<h2>C</h2>
Explanation:
2.0 × 10^3 is the correct form for writing any term in scientific notation form.
Comment for understanding anything.
We need to use the formula P = IV, where P is the power, I is the current and V is the voltage.
When we substitute our values in, we get:
100 = 240I, and so I = 0.42 Amps
Now, we have to work out the Resistance in the circuit at the operating temperature.
We do this using the formula V = IR
240 = (100/240) x R, and we get R = 576 Ohms
Since the resistance has gone up by a factor of 16, all we have to do now is to divide this answer by 16 to get the resistance at room temperature.
576/16 = 36 Ohms
Hope I helped!! xx
Answer:
not work
Explanation:
in a series circuit, everything meaning the electrons are flowing on one path, therefore, it wouldn continue to work.
