Yeah it’s My favorite I’m really excellent in Math That’s My 1st favorite subject
I can't exactly SHOW you where to put the numbers, but I can teach you the process of how you'd do it.
First off, label your number line from 0-15, as it is the simplest. (You'd be counting by 1 per each line). Then, follow this process:
1) Look at the first digit of your value. Place your number according to your first digit. (So, you'd put 0.365 at the 0 line and 3.521 at the 3 line)
2) Look at the second digit of your value. Imagine that between the two main lines (0-1 and 3-4) that there is 10 smaller lines. Then, you can place your number according to your second digit. (So, you'd put 0.365 at the 0.3 line and 3.521 at the 3.5 line).
3) Look at the third digit of your value. Imagine that between the two smaller lines (0.3-0.4 and 3.5-3.6) that there is 10 smaller lines. Then, you can place your number according to your third digit. (So, you'd put 0.365 at the 0.36 line and 3.521 at the 3.52 line).
4) Look at the fourth digit of your value. Imagine that between the two even smaller lines (0.36-0.37 and 3.52-3.53) that there is 10 smaller lines. Then, you can place your number according to your fourth digit. (So you'd place 0.365 at the 0.365 line and 3.521 at the 3.521 line)
Answer:
The length and width are 11ft and 5ft respectively
Step-by-step explanation:
let the
length = L
Width = W
Area = LW = 55
The length is nine feet less than four times the width
L = 4W - 9
W (4W - 9) = 55
4W^2 - 9W -55 = 0
4W^2 - 20W + 11W - 55 = 0
4W(W - 5) + 11(W - 5) = 0
(W - 5)(4W + 11) = 0
W - 5 = 0 , 4W + 11=0
W = 5 or - 11/4
since the width cannot be negative, W = 5
LW = 55
L = 55/5
L = 11
The length and width are 11ft and 5ft respectively.
Answer:
9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch
Step-by-step explanation:
Diameter of reamed hole = 0.278 inch
Radius of reamed hole = 
Surface area of reamed hole = 
Surface area of reamed hole = 
Surface area of reamed hole = 0.06066794
Diameter of pin = 
Radius of pin =
Surface area of pin = 
Since the surface area of pin is more than the surface area of hole .
So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch