<u>Answer:</u> The value of
for the reaction is 6.32 and concentrations of
is 0.094 M, 0.094 M and 0.106 M respectively.
<u>Explanation:</u>
Relation of
with
is given by the formula:

where,
= equilibrium constant in terms of partial pressure = 3.45
= equilibrium constant in terms of concentration = ?
R = Gas constant = 
T = temperature = 500 K
= change in number of moles of gas particles = 
Putting values in above equation, we get:

The equation used to calculate concentration of a solution is:

Initial moles of
= 1.00 mol
Volume of the flask = 5.00 L
So, 
For the given chemical reaction:

Initial: 0.2 - -
At Eqllm: 0.2 - x x x
The expression of
for above reaction follows:
![K_c=\frac{[(CH_3)_2C=CH]\times [HCl]}{[(CH_3)_3CCl]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B%28CH_3%29_2C%3DCH%5D%5Ctimes%20%5BHCl%5D%7D%7B%5B%28CH_3%29_3CCl%5D%7D)
Putting values in above equation, we get:

Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration
Calculating the concentration of reactants and products:
![[(CH_3)_2C=CH]=x=0.094M](https://tex.z-dn.net/?f=%5B%28CH_3%29_2C%3DCH%5D%3Dx%3D0.094M)
![[HCl]=x=0.094M](https://tex.z-dn.net/?f=%5BHCl%5D%3Dx%3D0.094M)
![[(CH_3)_3CCl]=(0.2-x)=(0.2-0.094)=0.106M](https://tex.z-dn.net/?f=%5B%28CH_3%29_3CCl%5D%3D%280.2-x%29%3D%280.2-0.094%29%3D0.106M)
Hence, the value of
for the reaction is 6.32 and concentrations of
is 0.094 M, 0.094 M and 0.106 M respectively.