1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elixir [45]
2 years ago
12

Help please it’d be greatly appreciated lol

Chemistry
2 answers:
Reil [10]2 years ago
5 0

6. c: electrons

7. a : Na and Cu

omeli [17]2 years ago
3 0

6. c: electrons

7. a: Na and Cu

You might be interested in
A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th
pogonyaev

Answer:

\boxed {\boxed {\sf 60 \%}}

Explanation:

Percent yield is a ratio of the actual yield to the theoretical yield. It is found using this formula:

\% \ yield= \frac {actual \ yield}{theoretical \  yield} *100

The actual yield is 12 liters, because that was actually produced in the lab.

The theoretical yield is 20 liters, because that was the expected yield.

\% \ yield= \frac {12 \ L}{20\ L} *100

\% \ yield= 0.6*100

\% \ yield= 60

For this reaction, the percent yield is 60%.

5 0
3 years ago
4.564000 x 10^-4 express how many significant figures
Vaselesa [24]

Answer: 7

Explanation:

Before a number but after a decimal. The zeros at the end would usually mean that it doesn't count but since the numbers are before the zeros and after a decimal it's 7 sig figs

5 0
3 years ago
Which of the following is accurate in describing the placement and classification of iodine?
fenix001 [56]
You can answer this question by only searching the element in the periodic table.

The atomic number of iodine, I, is 53. It is placed in the column 17 (this is the Group) and row 5 (this is the Period).

The conclusion is that the iodine is located in Period 5, Group 17, and is classified as a nonmetal.
4 0
3 years ago
When you need to produce a variety of diluted solutions of a solute, you can dilute a series of stock solutions. A stock solutio
8090 [49]

Answer:

Volume of stock solution needed = 6.0299 mL

Explanation:

<u> </u>Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

<u>Data:</u>

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL

4 0
3 years ago
in this cut-away image of an atom, where is the red arrow most likely pointed at the greatest probability of locating an electro
emmasim [6.3K]

Answer:

c

Explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • Draw the Lewis structure of H2O. Include any nonbonding electron pairs. Draw the molecule by placing atoms on the grid and conne
    7·1 answer
  • The pressure of a mixture of nitrogen, carbon dioxide, and oxygen is 300 kPa. What is the partial pressure of oxygen if the part
    7·1 answer
  • Greenhouse effect in a sentence and word to study
    10·1 answer
  • Why does Earth rotate?
    12·2 answers
  • How many moles of h2so4 are needed to make 85 ml of .750 m solution?
    9·1 answer
  • Which of these illustration shows isotopes of the elements boron b
    9·1 answer
  • What is the frequency of an X-ray that has a wavelength of 1.5 x 10 -9 m? The speed of electromagnetic radiation is 3.0 x 10 8 m
    12·1 answer
  • Based on the crystal- field strength cl-
    11·1 answer
  • During a reaction, H for reactants is -750 kJ/mol and H for products is 920 kJ/mol. Which statement is correct about the reactio
    10·1 answer
  • 3. Write balanced ionic equations to show the dissolution of the following compounds in water: a) magnesium chloride​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!