Answer:
Force = 6.25
so here correct option is a. 6.25
Explanation:
given data
resistance = 0.05 Ω
uniform magnetic field = 0.5 T
time = 0.1 s
to find out
maximum value of the force acting on the bar during that time
solution
we use here Faraday law of induction in the term of current
and solve here for I via the ohms law instead of the emf
That is end up by dividing by resistance
so here I will be
I = ..............1
I =
I = 25 A
and now l is length of 1 side of square when we solving for the force that is
Force = N*I²*B
Force = 1 ×25×0.5×0.5
Force = 6.25
so here correct option is a. 6.25
Answer:
137.8 N
Explanation:
First we need to find the acceleration of the sprinter. To do so, we can use the Torricelli's equation:
V^2 = Vo^2 + 2*a*S
9^2 = 2^2 + 2*a*25
81 = 4 + 50a
50a = 77
a = 77/50 = 1.54 m/s2
Now, to find the resulting force in the sprinter, we can use the following equation:
Force = mass * acceleration
Force = 70 * 1.54 = 107.8 N
If we have a 30 N force against the sprinter, the total force applied is:
Resulting force = Applied force - Wind force
107.8 = Applied force - 30
Applied force = 137.8 N
To solve the problem it is necessary to
apply the concept of Load on capacitors.
The charge Q on the plates is proportional
to the potential difference V across the two
plates.
It can be mathematically defined as:
0= CV
Where.
C= Capacitance
V= Voltage
Our values are given as,
C
= 0.60pF
V=30V
Substituting values in the above formula,
we get
Q= CV
Q
= 0.6 * 30
Q
= 18pC
Where
1pC= 10-12Coulomb
Therefore the charge must be 18pC to
Create a 30V pore potential difference