Question

1. A block with mass 20 kg is

Answer 1

Answer: 0.435 m

Explanation:

Given

mass m=20 kg

initial speed u=2 m/s

coefficient of kinetic friction $\mu_k=0.3$

deceleration which opposes the motion is given by

$\Rightarrow a=g\sin \theta+\mu_kg\cos \theta\\\Rightarrow a=g(\sin \theta +\mu_k\cos \theta)$

$\Rightarrow a=9.8(\sin 10^{\circ}+0.3\times \cos 10^{\circ})\\\Rightarrow a=4.59\ m/s^2$

using $v^2-u^2=2as$

$\Rightarrow s=\dfrac{2^2}{2\times 4.59}=0.435\ m$