Answer:
The orbital period of the planet would be half that of the earth
Explanation:
From the question we are told that
The mass of star is four times the mass of sun which can be mathematically represented as
Mathematically gravitational potential is given as
Where M is mass one
m is mass two
From this equation we see that the attraction force is directly proportional to the mass of the star
Thus we can say that
The centrifugal force that balances this attraction Force is
Where is the centrifugal acceleration which can be mathematically represented as
and m is the mass
Substituting this into the equation for centrifugal force
substituting into the equation above
Given that the diameter is the same and assuming that the mass is constant
Then
Take square root of both sides
As long as you describe the chemical reactions within the torpedo and explain how torpedoes advanced modern warfare.
Answer:
For mass m 1 newton 2nd law
F=m 1 a 1
5=m 1 ×10
m 1 = 2
1
kg
For mass m 2
F=m 2 a 2
5=m 2
×20
m 2
= 4
1 kg
if tied together
Total mass =m 1 +m 2 = 1/2 +1/4=3/4kg
Now
F=M
T Q
T
a T = 5/m T = 5×4/3 = 3
/20m/s^2
Explanation:
Answer:
E. 0.25
Explanation:
Given that
Angular speed ω = 3.5 rad/s
Distance ,r= 0.2 m
Lets take mass of dust bunny = m
We know that
Radial force F = m ω² r
The friction force on the dust bunny Fr
Fr= μ m g
To getting slung off dust bunny from disk
m ω² r = μ m g
ω² r = μ g
3.5² x 0.2 = μ x 10 ( take g =10 m/s²)
μ = 0.245
μ = 0.25
Therefore answer is E
E. 0.25
Answer:
Current, I = 0.0011 A
Explanation:
It is given that,
Diameter of rod, d = 2.56 cm
Radius of rod, r = 1.28 cm = 0.0128 m
The resistivity of the pure silicon,
Length of rod, l = 20 cm = 0.2 m
Voltage,
The resistivity of the rod is given by :
R = 893692.30 ohms
Current flowing in the rod is calculated using Ohm's law as :
V = I R
I = 0.0011 A
So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.