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madam [21]
3 years ago
14

A man plans to use a 2 metre crowbar to lift a rock by putting a pivot 0,8 m from

Physics
2 answers:
miv72 [106K]3 years ago
6 0
The answer is 0.58 meters. I agree with the working shown below. I did the same on paper, and it is the right answer. 
sp2606 [1]3 years ago
4 0
1.  The man will be able to move the rock.  See diagram.
     Moment of Man's force :  400 N * 1.2 meter  = 480 N-m
       Rock's Weight = 50 Kg * 9.8 m/sec²  = 490 Newtons
     Moment of Rock's weight  : 490 N * 0.80 meters = 392 N-m
    
  <em><u>   Moment of Man's Force is MORE :  480 N-m > 392 N-m</u></em>
<em><u>     So man will be able to lift the rock.</u></em>

2. Let is look at the diagram - second one.
     Let us assume that the fulcrum (Pivot) is placed at X meters from the rock.
     So moment of Girl's force about Pivot =  200 N * (2 - X) meters = 400 - 200 X
         Moment of Rock's weight = 490 N * X = 490 X

     As the Girl is able to lift the rock,  400 - 200 X  >  490 X
       Hence      400 >  200 X + 490 X
                      400 >  690 X
                       X <  400/690  =  0.58 meters
    <u><em> If the Pivot is placed closer than 0.58 meters or 58 cm to the Rock, then </em></u>
<u><em>     she can lift the rock.</em></u>

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3. A pendulum with a 1.0-kg weight is set in motion from a position 0.04 m above the lowest point on the path of the weight.
gavmur [86]

Answer: K.E = 0.4 J

Explanation:

Given that:

M = 1.0 kg

h = 0.04 m

K.E = ?

According to conservative of energy

K.E = P.E

K.E = mgh

K.E = 1 × 9.81 × 0.04

K.E = 0.3924 Joule

The kinetic energy of the pendulum at the lowest point is 0.39 Joule

6 0
3 years ago
A ship travels with velocity given by 12, with current flowing in the direction given by 11 with respect to some co-ordinate axe
nataly862011 [7]

Answer:

v_x = 11.78 m/s

Explanation:

Velocity of the ship is given as

v = 12 units

the direction of the velocity of the ship is making an angle of 11 degree with the current

so we will have two components of the velocity

1) along the direction of the current

2) perpendicular to the direction of the current

so here we know that the component of the ship velocity along the direction of the current is given as

v_x = v cos\theta

v_x = 12 cos11

v_x = 11.78 m/s

7 0
3 years ago
Question 1 (1 point)
deff fn [24]

Answer:

Travelled 18 km, they are 6 km from home.

Explanation:

12/2 (halfway) is 6km. So, 6 + 12 would be 18 km, total amount travelled. The total distance of the trip would be 24 km (12 km out, 12km back) if they travelled 12+6 (18km) then they only have 6 km more to go.

5 0
3 years ago
A farsighted boy has a near point at 2.3 m and requires eyeglasses to correct his vision. Corrective lenses are available in inc
tino4ka555 [31]

Answer:

P = 3.5 D

Explanation:

As we know that convex lens is to be used to make the near point of eye to be correct

So we will have

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

here we have

d_i = 2.3 m = 230 cm

d_o = 25 cm

now plug in all values into the formula

-\frac{1}{230} + \frac{1}{25} = \frac{1}{f}

f = 28 cm

now for power of lens

P = \frac{1}{f}

P = \frac{1}{0.28} = 3.5 D

so the power in dioptre is

P = 3.5 D

5 0
3 years ago
The gymnast has a mass of 45 kg gravitational field strength = 9.8 N/kg - Calculate the weight of the gymnast. Use the equation:
tia_tia [17]

Answer: B. The gravitational field strength of Planet X is Wx/m.

Explanation:

Weight is a force, and as we know by the second Newton's law:

F = m*a

Force equals mass times acceleration.

Then if the weight is:

Wx, and the mass is m, we have the equation:

Wx = m*a

Where in this case, a is the gravitational field strength.

Then, isolating a in that equation we get:

Wx/m = a

Then the correct option is:

B. The gravitational field strength of Planet X is Wx/m.

7 0
3 years ago
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