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dezoksy [38]
2 years ago
15

Which of the following correctly gives the center and radius of the circle defined by the equation

Mathematics
1 answer:
andrezito [222]2 years ago
3 0

Answer:

The center is =(3,−2) = 3

Step-by-step explanation:

Factorise(x−3)2+(y+2)2=32

The center is =(3,−2) and the radius is =3

graph{(x^2+y^2-6x+4y+4)=0 [-14.08, 8.11, -5.51, 5.58]}

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solmaris [256]
I possibly think it is c that is what I got
8 0
3 years ago
a mixture of peanuts and corn sells for P40 per kilo. The peanuts sell for P42 per kilo while the corn sells for P36 per kilo. h
Lelu [443]

Answer:

The weight of peanuts in the mixture   = 8  kg

The weight of corns in the given mixture = 4 kg

Step-by-step explanation:

Let us assume the weight of peanuts in the mixture   = x kg

The weight if corns in the given mixture = y kg

Total weight = (x + y) kg

The combined mixture weight = 12 kg

⇒ x  + y = 12  ..... (1)

Cost of per kg if mixture  = $ 40

So, the cost of (x + y) kg mixture  = (x+y) 40 = 40(x+ y)   ..... (2)

 

The cost of 1 kg of peanuts =  $ 42

So cost of x kg of peanuts  = 42 (x)  = 42 x

The cost of 1 kg of corns  = $ 36

So cost of y kg of corns  = 36 (y)  = 36 y

So, the total cost of x kg peanuts  + y kg corns =  42 x +  36 y  .... (3)

From (1) and (2), we get:

40(x+ y)  = 42 x +  36 y

x +  y = 12 ⇒ y = 12 -x

Put this in  40(x+ y)  = 42 x +  36 y

We get:

40(x+ 12 -x)  = 42 x +  36 (12 -x)

480 = 42 x + 432 - 36 x

or, 480 - 432 = 6 x

or, x  = 8

⇒ y = 12 -x = 12 - 8 = 4

⇒  y = 4

Hence, the weight of peanuts in the mixture   = 8  kg

The weight of corns in the given mixture = 4 kg

5 0
3 years ago
stan, a local delivery driver is paid $3.50 per mile driven plus a daily amount of $75. on monday he is assigned a route that is
Kisachek [45]

Just do an equation. 3.5(30)+75=180

7 0
3 years ago
Read 2 more answers
Suppose you multiply a whole number greater than one by the fraction 3/5. will the product be greater than less than or equal to
Damm [24]
Ittttts obviously be greater than   3/5 
 5 * 3/5 to get 3!!
5 0
3 years ago
If x = √3 − √2 , find the value of ( −1/x)root 2
makkiz [27]

hello

\dfrac{-1}{x}\sqrt{2}=\dfrac{-\sqrt{2}}{\sqrt{3}-\sqrt{2}}=\dfrac{-\sqrt{2}(\sqrt{3}+\sqrt{2})}{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})}\\\\=\dfrac{-\sqrt{2}(\sqrt{3}+\sqrt{2})}{3-2}\\\\=-\sqrt{6}-2

hope this helps

8 0
3 years ago
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