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dezoksy [38]
2 years ago
15

Which of the following correctly gives the center and radius of the circle defined by the equation

Mathematics
1 answer:
andrezito [222]2 years ago
3 0

Answer:

The center is =(3,−2) = 3

Step-by-step explanation:

Factorise(x−3)2+(y+2)2=32

The center is =(3,−2) and the radius is =3

graph{(x^2+y^2-6x+4y+4)=0 [-14.08, 8.11, -5.51, 5.58]}

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Express as a difference: a+b, a+5
Tcecarenko [31]

Answer:

a - (-b), a - (-5)

Step-by-step explanation:

A double negative negative is a positive, so a - (-b) = a + b, and a - (-5) is a + 5. However, a double negative is still a difference, so this answer works.

6 0
2 years ago
The graph of the function f(x) = tan x is given above for the interval x in[0,2 pi] NL Determine the one-sided limit. Then indic
damaskus [11]

Okay, here we have this:

Considering the provided function, we are going to calculate the requested one-side limits, so we obtain the following:

5 0
1 year ago
The function g is a transformation of f. If g has a y-intercept at -1, which of the following functions could represent g?
scZoUnD [109]
The answer is C. G(x)= f(x) -1
4 0
3 years ago
What is the inverse of the function?<br> f(x) = 1/3x-5
OlgaM077 [116]

Answer:

        -1

       f   (x) = -3(x + 5)

Step-by-step explanation:

1)  in f(x) = 1/3x-5, replace f(x)= with y= as follows:  y = (1/3)x - 5

2) interchange x and y, obtaining:  x = (1/3)y - 5

3) solve this result for y:  (1/3)y = -x - 5, or -(x + 5).  Next, multiply both sides by                        3 to eliminate the fraction (1/3):  y = -3(x + 5)

4)  replace y with the symbol for "inverse of f(x);

        -1

       f   (x) = -3(x + 5)

5 0
3 years ago
Hey can you please help me!
melisa1 [442]

Answer:


Step-by-step explanation:

1) Tangent makes 90 degrees with the radius. Hence

a) Angle ABD = 90-angle BDC = 90-61.3 = 28.7

b) Triangle BCD is isosceles since tangents have equal length.

Hence angle BCD = 180-(61.3+61.3) = 57.4

c) Angle BDC = 57.4 (since triangle BCD is isosceles)

d) Angle BAC and Angle BCD are supplementary. Hence angle BAC = 122,6

-------------------------------------------

2) Arc length of minor arc BC = \frac{79.3}{360} (24) = 5.287

b) ARc length of minor arc = circumference -minor arc

= 18.713

---------------------------------------------

3) circumference = pi d = 3.14(9) = 28.26


6 0
3 years ago
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