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SIZIF [17.4K]
3 years ago
11

Please help fast

Physics
1 answer:
vaieri [72.5K]3 years ago
8 0

D.sound insulators prevent from being transmitted better than elastic solids

Explanation:

The correct option from the given choices is that, sound insulators prevent sound from being transmitted better than elastic solids.

Sound is a form of wave that transmits energy from one point to another.

This wave form is a longitudinal wave in nature.

During the propagation of sound, it requires a material medium to move.

Sound insulators are special materials designed not to transmit sound energy.

Such materials cuts off sound. They are better than elastic solids in preventing sound transmission.

learn more:

Sound wave brainly.com/question/3619541

#learnwithBrainly

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What amount of heat is required to raise the temperature of 25 grams of copper to cause a 15ºC change? The specific heat of copp
Lina20 [59]

The amount of heat required is B) 150 J

Explanation:

The amount of heat energy required to increase the temperature of a substance is given by the equation:

Q=mC\Delta T

where:

m is the mass of the substance

C is the specific heat capacity of the substance

\Delta T is the change in temperature of the substance

For the sample of copper in this problem, we have:

m = 25 g (mass)

C = 0.39 J/gºC (specific heat capacity of copper)

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Substituting, we find:

Q=(25)(0.39)(15)=146 J

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brainly.com/question/3032746

brainly.com/question/4759369

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3 years ago
Starting from rest, a disk rotates about its central axis with constant angular acceleration. in 6.00 s, it rotates 44.5 rad. du
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a. The disk starts at rest, so its angular displacement at time t is

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It rotates 44.5 rad in this time, so we have

44.5\,\mathrm{rad}=\dfrac\alpha2(6.00\,\mathrm s)^2\implies\alpha=2.47\dfrac{\rm rad}{\mathrm s^2}

b. Since acceleration is constant, the average angular velocity is

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where \omega_f is the angular velocity achieved after 6.00 s. The velocity of the disk at time t is

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Another way to find the average velocity is to compute it directly via

\omega_{\rm avg}=\dfrac{\Delta\theta}{\Delta t}=\dfrac{44.5\,\rm rad}{6.00\,\rm s}=7.42\dfrac{\rm rad}{\rm s}

c. We already found this using the first method in part (b),

\omega=14.8\dfrac{\rm rad}{\rm s}

d. We already know

\theta=\dfrac\alpha2t^2

so this is just a matter of plugging in t=12.0\,\mathrm s. We get

\theta=179\,\mathrm{rad}

Or to make things slightly more interesting, we could have taken the end of the first 6.00 s interval to be the start of the next 6.00 s interval, so that

\theta=44.5\,\mathrm{rad}+\left(14.8\dfrac{\rm rad}{\rm s}\right)t+\dfrac\alpha2t^2

Then for t=6.00\,\rm s we would get the same \theta=179\,\rm rad.

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