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____ [38]
3 years ago
12

Frame S' passes frame S in the usual way (positive directions). An object also moves in the positive direction. Which is true? T

he object's speed relative to S is greater than its speed relative to S'. The object's speed relative to S can be greater than or less than its speed relative to S', depending on the actual values. The object's speed relative to S is equal to its speed relative to S'. The object's speed relative to S is less than its speed relative to S'.
Physics
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

The answer is "The object's speed relative to S can be greater than or less than its speed relative to S', depending on the actual values."

Explanation:

The S' frame and the object are moving in a positive direction. The object is moving with respect to the S frame so the S frame the rest frame

take the velocity of the object with respect to the rest frame as v and the velocity of the S' frame with respect S frame as v2

relative velocity of the object to the S' frame would be

Vrel = v2- v

This means the Vrel of the object with respect to the S' frame is less than the Vrel  of the object with respect to the S frame

However is the S' velocity is greater than that of the object then the Vrel of the object with respect to the S' frame is greater than the Vrel of the object with respect to the S frame.

This would mean the second option is the answer, the relative speed of the object depends on the actual values.

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Find the unknown mass of the block 1 needed to balance the bar. Assume that the mass of the bar is negligible. Block 1 is locate
Natasha2012 [34]

Answer:

Incomplete question: The masses of the blocks m₂ = 1.5 kg and m₃ = 2 kg

Explanation:

Given data:

L₁ = length = 0.85 m

L₂ = 0.25 m

L₃ = 0.5 m

m₂ = 1.5 kg

m₃ = 2 kg

Question: Find the unknown mass of the block 1 needed to balance the bar, m₁ = ?

The torque is zero (intermediate point of the bar)

-m_{1} gL_{1} +m_{2} gL_{2} +m_{3} gL_{3} =0

Is negative because mass 1 is to the left of the coordinate system (see the diagram)

m_{1} =\frac{m_{2} gL_{2}+m_{3} gL_{3}  }{L_{1} } =\frac{(1.5*0.25)+(2*0.5)}{0.85} =1.6176kg

4 0
3 years ago
Average speed equals distance divided by time. on a journey to the
Tanzania [10]

The average speed will be 2.38×10⁶ m/sec.The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

<h3>What is the average speed?</h3>

The total distance traveled by an object divided by the total time taken is the average speed.

The speed calculated at any particular instant of time is known as the instantaneous speed.

Given data;

Distance travelled = 4.12x10¹⁶ meter

Time period= 1.73x10¹⁰ sec

The average speed is found as

\rm V_{avg}= \frac{d}{t} \\\\\ \rm V_{avg}= \frac{4.12 \times 10^{16}}{1.73 \times 10^{10} } \\\\\ V_{avg}=2.38 \times 10^6 \ m/sec

Hence, the average speed will be 2.38×10⁶ m/sec.

To learn more about the average speed, refer to the link;

brainly.com/question/12322912

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How would you classify an EM wave with a frequency of 10^7 Hz?
tiny-mole [99]

Answer:

I think it is television and radio wave

5 0
3 years ago
Please answer! thank you!
lesantik [10]

Answer:

Maybe A.... I'm not sure

Explanation:

8 0
2 years ago
Read 2 more answers
A 4.0 kg mass is attached to a spring whose spring constant is 950 N/m. It oscillates with an amplitude of 0.12 m. What is the m
Fudgin [204]

Answer:

velocity = 2.62m/s

Explanation:

950= (4 x A)/0.12

950 x 0.12 = 4 x A

114 = 4 x A

A = 114/4

A = 28.5m/s²

  • U²=2as
  • U² = 2 x 28.5 x 0.12
  • U² = 6.84
  • U = √6.84
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3 0
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