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prohojiy [21]
3 years ago
11

An organisms ___________ adaptations are its physical traits that help it survive in its environment.

Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:c

Explanation:

I think

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6. What parts of a nuclear reactor keep the reaction from
Shalnov [3]

Answer:

B. control rods and moderators

5 0
3 years ago
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PLEASE HELP AND EXPLAIN!Calculate the energy required to heat 187.0 g of ammonia from 36.1 °C to 52.9 °C. Assume the specific he
Alenkinab [10]

Answer:

E=1.48x10^4J

Explanation:

Hello!

In this case, since the energy implied in a heating process is computed by using the following equation:

E=mC(T_f-T_i)

Whereas m is the mass, C the specific heat and T the temperature. In such a way, by plugging in the given mass, specific heat and temperatures, we obtain the following energy:

E=187.0g*4.703\frac{J}{g\°C} (52.9\°C-36.1\°C)\\\\E=1.48x10^4J

Considering that the specific heat can by used by unit of °C or K because their difference is equivalent.

Regards!

3 0
3 years ago
An object in motion has what type of energy?
Alisiya [41]

Answer:

B) Kinetic

Explanation:

Kinetic Energy is energy relating to or resulting from motion. Therefore, the answer to this question is B.

8 0
3 years ago
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Carbon is often called "the building block of life". If your body is 18% carbon, what mass
Svetradugi [14.3K]

Answer:

oxygen

Explanation:

I am pretty sure it is that but you should still check

4 0
3 years ago
B) calculate the ratio of moles of h2o to moles of anhydrous kal(so4)2. note: report the ratio to the closest whole number. (sho
Sindrei [870]

Answer: -

Mass of Hydrated KAl(SO₄)₂ = 2.0 g

Molar mass of anhydrous KAl(SO₄)₂ = 258.20 g/ mol

Mass of of anhydrous KAl(SO₄)₂ = mass of the 2nd heating = A

The mass of water released = mass of the Aluminum Cup + 2.0 grams of KAl(SO₄)₂ - mass of the 2nd heating

= H g

Moles of water released = \frac{H g}{18 g/mol}

Moles of anhydrous KAl(SO₄)₂ = \frac{A g}{258.20 g/mol}

Required ratio = \frac{moles of water}{moles of anhydrous KAl(SO4)2}

5 0
3 years ago
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