Answer:
spring tide
Explanation:
When the sun, moon, and Earth are in alignment (at the time of the new or full moon), the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides — both commonly called spring tide
Hello!
We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)
C: 70.79% = 70,79 g
H: 8.91% = 8.91 g
N: 4.59% = 4.59 g
O: 15.72% = 15.72 g
Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:




We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:




T<span>hus, the minimum or empirical formula found for the compound will be:
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I hope this helps. =)
Answer:
3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)
Explanation:
This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.
Answer:
C.) 76.1 grams
Explanation:
To find the mass of bromine, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass), then (2) convert moles AlCl₃ to moles Br₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Br₂ to grams Br₂ (via molar mass). It is important to arrange your ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).
Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)
Molar Mass (AlCl₃): 133.332 g/mol
2 AlCl₃ + 3 Br₂ --> 2 AlBr₃ + 3 Cl₂
Molar Mass (Br₂): 2(79.904 g/mol)
Molar Mass (Br₂): 159.808 g/mol
42.3 g AlCl₃ 1 mole 3 moles Br₂ 159.808 g
------------------ x ----------------- x ---------------------- x ------------------- =
133.332 g 2 moles AlCl₃ 1 mole
= 76.0 g Br₂
*Our answers are slightly different most likely because we used slightly different molar masses*