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prohojiy [21]
3 years ago
11

An organisms ___________ adaptations are its physical traits that help it survive in its environment.

Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:c

Explanation:

I think

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PLEASE HELP WILL GIVE BRAINLIEST!!!
IrinaVladis [17]

Answer:

The light emitted by a light bulb is a form of radiation that occurs when the filament heats up and its thermal emission gains enough energy to move into the visible spectrum.

Explanation:

Light bulbs contain a filament which is heated up electrically. When this filament is heated up,energy in the form of heat is imparted to the electrons in the filament.

This thermal excitation of electrons ultimately leads to emission of light in the viable spectrum. This light is now radiated through a light bulb.

6 0
3 years ago
Match the function to the part of the cell.
Arada [10]
Lysosome is B. breaks down waste materials

Vacuole is A. temporary storage

Chloroplast is C. converts energy
7 0
2 years ago
Choose all the answers that apply.
Arada [10]

Answer:

removing topsoil

Explanation:

5 0
2 years ago
Read 2 more answers
A balloon filled with helium occupies 20.0 l at 1.50 atm and 25.0◦c. How many moles of helium will there be in the balloon at st
satela [25.4K]

Answer:

  • There will be 1.23 moles of helium in the balloon at STP

Explanation:

1) <u>Initial conditions of the helium gas</u>:

  • V = 20.0 liter
  • p = 1.50 atm
  • T = 25.0 °C = 25.0 + 273.15 K = 298.15 K

2) <u>Ideal gas equation</u>:

  • pV = n RT
  • p, V, and T are given above
  • R is the Universal constant = 0.0821 atm-liter / ( K - mol)
  • n is the unknown number of moles

3) <u>Solve for n</u>:

  • n = pV / (RT) =
  • n = 1.50 atm × 20.0 liter / (0.0821 atm-liter /k -mol ×298.15K)
  • n = 1.23 mol

4) <u>At STP:</u>

  • STP stands for standard pressure and temperature.
  • The amount (number of moles) of the gas will not change because the change of pressure and temperature, so the number of moles reamain the same: 1.23 mol.
8 0
3 years ago
Determine the volume occupied by 0.352 mole of a gas at 25⁰C if the pressure is 81.8 kPa.
lions [1.4K]
Data:
p (pressure) = 81.8 kPa = 81.8*10³ Pa ≈ 8.07 atm
v (volume) = ? (in L)
n (number of mols) = 0.352 mol
R (Gas constant) = 0.082 (atm*L/mol*K)
T (temperature) = 25ºC converting to Kelvin, we have:
TK = TC + 273 → TK = 25 + 273 → TK = 298

Formula:
p*V =n*R*T

Solving:
p*V =n*R*T
8.07*V = 0.352*0.082*298
8.07V \approx 8.60
V \approx  \frac{8.60}{8.07}
\boxed{\boxed{V \approx 1.06\:L}}
7 0
3 years ago
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