All categories

3 years ago

PLEASE HELP MEEE THIS NEEDS TO BE DONE IN HALF AN HOUR :(

Chemistry

1 answer:

AveGali [126]3 years ago

4 0

D is the answer.Brainliest?!?

You might be interested in

How should the baking of a pizza be categorized

MrMuchimi

<h2>The baking of a Pizza be Categorize as Endothermic Process</h2>

The baking of a pizza should be categorized as an endothermic process because the dough absorbs heat. An endothermic process is a method that absorbs energy from its surroundings which is habitually in the form of energy.

It can be a biochemical process like solving the salt in water or just the melting of ice. Therefore, the dough absorbs heat and it is categorized as an endothermic process.

3 0

3 years ago

Read 2 more answers

Help me with these two please

prohojiy [21]

Answer:

13.A

14.B?

on 14 i don't know

Explanation:

3 0

3 years ago

Read 2 more answers

Acetanilide has a solubility of 1.00 g/185 ml in 25 oc water and 1.00 g/20 ml in 100 oc water. what is the minimum volume of wat

Likurg_2 [28]

In the crystallization process the solid compound is dissolved in the solvent at elevated temperature and the crystallize product obtained by slow cooling of the solution. Here the solubility of acetanilide at 100°C is 1g per 20mL of water. Thus to dissolve 500mg of acetanilide at high temperature that is 100°C we need 10mL of water.

Now at 25°C after the re-crystallization there will be some amount of dissolve acetanilide. Which can be calculated as- 185mL of water is needed to dissolve 1g or 1000mg of acetanilide at 25°C. Thus in 10mL of water there will be $\frac{10X1000}{185}=54.05$ gmg of acetanilide.

6 0

4 years ago

The ability to put in a light bulb with greater ease is because the bottom half is what type of simple machine?

Travka [436]

A screw simple machine

4 0

3 years ago

The standard emf for the cell using the overall cell reaction below is +2.20 V:

ANEK [815]

Answer:

emf generated by cell is 2.32 V

Explanation:

Oxidation: $2Al-6e^{-}\rightarrow 2Al^{3+}$

Reduction: $3I_{2}+6e^{-}\rightarrow 6I^{-}$

---------------------------------------------------------------------------------

Overall: $2Al+3I_{2}\rightarrow 2Al^{3+}+6I^{-}$

Nernst equation for this cell reaction at $25^{0}\textrm{C}$ -

$E_{cell}=E_{cell}^{0}-\frac{0.059}{n}log{[Al^{3+}]^{2}[I^{-}]^{6}}$

where n is number of electrons exchanged during cell reaction, $E_{cell}^{0}$ is standard cell emf , $E_{cell}$ is cell emf , $[Al^{3+}]$ is concentration of $Al^{3+}$ and $[Cl^{-}]$ is concentration of $Cl^{-}$

Plug in all the given values in the above equation -

$E_{cell}=2.20-\frac{0.059}{6}log[(4.5\times 10^{-3})^{2}\times (0.15)^{6}]V$

So, $E_{cell}=2.32V$

3 0

3 years ago