PLEASE HELP MEEE THIS NEEDS TO BE DONE IN HALF AN HOUR :(

2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)

balandron [24]

The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

Learn more about stoichiometry:

brainly.com/question/14735801

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3 0

2 years ago

A proton in a linear accelerator has a de Broglie wavelength of 132 pm. What is the speed of the wavelength?

kherson [118]

Answer:

The speed of wavelength is 3.0 ×10³ m/s.

Explanation:

Given data:

De Broglie wavelength = 132 pm (132×10⁻¹² m)

Speed of wavelength = ?

Solution:

Formula:

λ = h/mv

λ = wavelength

h = planck's constant

m = mass of proton

v = speed

now we will put the values in formula.

132×10⁻¹² m = 6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × v

v = 6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m

j = kg m²/s²

v = 6.63 ×10⁻³⁴ kg m²/s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m

v = 6.63 ×10⁻³⁴ kg m²/s / 220.44 ×10⁻³⁹ kg.m

v = 0.03×10⁵ m/s

v = 3.0 ×10³ m/s

The speed of wavelength is 3.0 ×10³ m/s.

3 0

4 years ago

4. Which of the following is NOT a basic function of a cell?A. RespirationB. IngestionC. SleepingD. Reproduction

Yanka [14]

Explanation:

C. Sleeping

Hope it helps

8 0

3 years ago

Read 2 more answers

given a k value of 0.43 for the following aqueous equilibrium suppose sample z is placed into water such that its original conce

serious [3.7K]

Answer:

Less than 0.033 M:

$[Z]_{eq}=2.4x10^{-3}M$

Explanation:

Hello,

In this case, the described equilibrium is:

$2A+B\rightarrow 2Z$

Thus, the law of mass action is:

$K=\frac{[Z]^2}{[A]^2[B]}=0.43$

Nevertheless, given the initial concentration of Z that is 0.033 M, we should invert the equilibrium since the reaction will move leftwards:

$\frac{1}{K}=\frac{[A]^2[B]}{[Z]^2}=\frac{1}{0.43}=2.33$

Know, by introducing the change $x$ due to the reaction extent, we can write:

$2.33=\frac{(2x)^2*x}{(0.033-2x)^2}$

Which has the following solution:

$x_1=2.29M\\x_2=0.0181M\\x_3=0.0153M$

But the correct solution is $x_3=0.0152M$ since the other solutions make the equilibrium concentration of Z negative which is not possible. In such a way, its concentration at equilibrium is:

$[Z]_{eq}=0.033M-2(0.0153M)$

$[Z]_{eq}=2.4x10^{-3}M$

Which is clearly less than 0.033 M since the addition of a product shift the reaction leftwards in order to reestablish equilibrium (Le Chatelier's principle).

Regards.

6 0

3 years ago

Select the answer which shows the correct order, slowest to fastest, of the relative rate of diffusion of the gases.

IrinaK [193]

Diffusion is the process of a substance spreading out to evenly fill its container or environment. Rate of diffusion of a gas is inversely proportional to the molar mass of the gas.

$Rate of diffusion \propto \frac{1}{Molar mass}$

Lighter(lower) the molar mass of the gas , faster will be its rate of diffusion and heavier (higher) the molar mass of the gas , slower will be its rate of diffusion.

We have to arrange the given gases from slowest rate of diffusion to fastest rate of diffusion that means we need to arrange gases from higher molar mass to lower molar mass.

Molar mass of given gases are :

Cl = 35.5 g/mol

Xe = 131.29 g/mol

He = 4.00 g/mol

N = 14.00 g/mol

So correct order for slowest rate of diffusion (highest molar mass) to fastest rate of diffusion (lowest molar mass) is :

Xe , Cl , N , He

Xe having the highest molar mass will have the slowest rate of diffusion and He with lowest molar mass will have the fastest rate of diffusion, so option 'c' is correct.

Note : Slowest rate of diffusion = High Molar Mass

Fastest rate of diffusion = Low Molar Mass

7 0

4 years ago