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3 years ago

Which possible answer can it be ?

Mathematics

2 answers:

Greeley [361]3 years ago

5 0

Wow this ones really hard...mmmmmm I thinks it’s...c

Vera_Pavlovna [14]3 years ago

4 0

It’s c
Just put it in a Calculator.
Ok it’s c.

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What is the slope of the line that contains the points (7, -3) and (-7, 4)?

tino4ka555 [31]

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$m = \dfrac{-3 - 4}{7 - (-7)}$

$m = \dfrac{-7}{14}$

$m = -\dfrac{1}{2}$

Answer: The slope is -1/2.

8 0

2 years ago

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Each month, Arnold receives $1,050 for working part time at his uncle’s camera store. For each camera that he sells, he earns a

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3 years ago

PLEASE HELP WORTH 99 POINTS AND CORRECT ANSWER WILL GET BRAINLIEST

Soloha48 [4]

Hello!

I believe the answers are:

A) The vertex is (1, −6)

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3 years ago

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Hot dogs are sold in packages of 8, and hot dog buns are sold in packages of 12. What's the smallest number of each that could b

PIT_PIT [208]

24 is the answer 8x3 = 24 12x2 = 24 8*3 = 12*2

7 0

3 years ago

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

2 years ago