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Hitman42 [59]
2 years ago
6

You serve a tennis ball of mass 60g at a speed of 50

Physics
1 answer:
gogolik [260]2 years ago
7 0

Answer:

J = 3~Kg.m/s

Explanation:

<u>Impulse and Momentum</u>

The impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it.

The equation can be written as follows:

J =\Delta p = p_2-p_1

Where:

J    = Impulse

p2 = Final Momentum

p2 = Initial Momentum

The momentum can be calculated as:

p = m.v

Where m is the mass of the object and v is the velocity.

The tennis ball with mass m=60 g = 0.06 Kg was served from rest (v1=0) to v2=50 m/s. The change in momentum is:

\Delta p = 0.06Kg~50~m/s-0

\Delta p = 3~Kg.m/s

Thus the impulse is:

\marhbf{J = 3~Kg.m/s}

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A grocery shopper tosses a(n) 8.5 kg bag of rice into a stationary 17.7 kg grocery cart. The bag hits the cart with a horizontal
timama [110]

Answer:

2.2386 m/s

Explanation:

I think you would use the momentum equation.

m1v1=m2v2

m1= mass of the bag (8.5kg)

v1= speed of bag (6.9 m/s)

m2= mass of bag and cart (26.2 kg)

v2= speed of cart and bag

Plug these numbers all into the equation and you solve for v2 which ends up at 2.2386 m/s

4 0
3 years ago
A 1090 kg car moving +11.0 m/s
stiks02 [169]

The mass of the second car is 1434.21 kg

<u>Explanation:</u>

Using law of conservation of momentum,

          m_{1} u_{1}+m_{2} u_{2}=\left(m_{1}+m_{2}\right) v

Given:

m_{1} = 1090 kg

u_{1} = 11 m/s

u_{2} = 0

v = 4.75 m/s

We need to find m_{2}

When substituting the given values in the above equation, we get

(1090 \times 11)+\left(m_{2} \times 0\right)=\left(1090+m_{2}\right) 4.75

11990=5177.5+4.75 m_{2}

4.75 m_{2}=11990-5177.5

4.75 m_{2}=6812.5

m_{2}=\frac{6812.5}{4.75}=1434.21 \mathrm{kg}

6 0
2 years ago
Please help
vladimir2022 [97]

Answer:

true true false true false

5 0
2 years ago
Read 2 more answers
How much heat energy (in megajoules) is needed to convert 7 kg of ice at -9°C C to water at 0°C?
Molodets [167]

Answer:

hence option A is correct

Explanation:

heat required from -9°C to 0°C ice = mass × specific heat of ice ×change in temperature

heat required from -9°C to 0°C ice = 7×2100×9 =132300 J =0.1323 MJ

( HERE SPECIFIC HEAT OF ICE IS A CONSTANT VALUE OF 2100

J/(kg °C )

heat required from  0°C ice to 0°C water = mass× specific heat of fusion of ice

                                                             = 7×3.36×10^5

                                                              = 2.352 × 10^6 J

                                                              = 2.352 MJ

TOTAL HEAT ENERGY REQUIRED = 0.1323 MJ +2.352 MJ

                                                          = 2.4843 MJ

hence option A is correct

5 0
2 years ago
What thrust does a 360 g model rocket need in order to have a vertical acceleration of 13.0 m/s2 on the earth?
maksim [4K]
Hope this helps u :)

5 0
3 years ago
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