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RSB [31]
2 years ago
12

Which has more mass: a stick of 4 counting cubes or a pile of 4 counting cubes?

Chemistry
1 answer:
sattari [20]2 years ago
4 0

i have thids quuuuesstttttttiopn

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The brightness of a star is determined by _____.
Travka [436]

Answer:

Size and Temperature or E & B

Explanation:

7 0
2 years ago
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Create a graphic representation that illustrates the steps from gene to protein. Label and describe each step.
Vesna [10]

Okay so,

1) Translation- show the RNA strand attatching to a DNA strand with the complimentary base pairs. introns are spliced

2) mRNA leaves the cell and joins with a ribosome

3) Transcription - tRNA (clover shaped) reads each codon (triplets) which each code for an amino acid. The stop codons on the end tell the tRNA that the chain is finished

4) the sequence forms the primary structure (all peptide bonds) which determines the shape of the secondary (hyrdogen and peptide) and hence determines the shape of the tertiary structure of a protein (ionic, hydrogen, disulfide bridges and hydrophibic interactions)


Hope this helps :)

6 0
3 years ago
What 4 words make up the acronym for NASA.
Nonamiya [84]
If you mean what the abbreviation stands for, NASA means <span>National Aeronautics and Space Administration. Hope this helps!!</span>
5 0
2 years ago
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Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us
BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0
3 years ago
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PLEASE ANSWER + BRAINLIEST !!!
MA_775_DIABLO [31]
Hope this would help you

5 0
3 years ago
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