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Gwar [14]
2 years ago
13

What will occur when potassium reacts with sulfur?

Chemistry
1 answer:
sveticcg [70]2 years ago
4 0
The electrons are transferred from potassium to sulphur, in this reaction, potassium is being oxidised and sulphur is being reduced. Two potassium atoms each lose one electron forming K+ ions. Sulphur gains two electrons forming S2-/2- ions. The resultant formula will be: K2S, bonding in this compound is ionic.
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What is the pH of 1.00 L of a buffer that is 0.110 M nitrous acid (HNO2) and 0.200 M NaNO2? (pKa of HNO2 = 3.40)
Andrei [34K]

Answer:

pH = 3.65    

Explanation:

given data

pKa of HNO2 = 3.40

nitrous acid (HNO2) = 0.110 M

NaNO2 = 0.200 M

to find out

What is the pH

solution

we get here ph for acidic buffer  that is express as

pH = pKa + log(salt÷acid)      ........................1

put here value and we get

pH = 3.40 + log(0.200÷0.110)

pH = 3.65    

4 0
3 years ago
Chromuate found inside which of the following structures of a eukaryotic cell?
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Answer:

Chromuates are found in the chromosomes of the eukaryotic cells!!!!

Explanation:

I learned this in 7th grade!!!!

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4 0
3 years ago
Choose the element that is more reactive: oxygen or argon.
Mazyrski [523]
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7 0
3 years ago
Which states of matter only appear in the hydrosphere
Oliga [24]
I would say the answer is liquids
7 0
2 years ago
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
BigorU [14]
Mg reaction with O₂ gas will produce MgO so the equation will be
2Mg+O₂⇒2MgO. (You have to find the equation in order two figure out the number of moles of O₂ that will react with 1 mole of MgO).

The first step is to find the number of moles of Mg in 4.03g of Mg.  You can do this by dividing 4.03g Mg by its molar mass (which is 24.3g/mol) to get 0.1658mol Mg.  Then you have to find the number of moles of O₂ that will react with 0.1658mol Mg.  To do this you need to use the fact that 1mol O₂ will react with 2mol Mg (this reatio is from the chemical equation) so you have to multiply 0.1658mol Mg by (1mol O₂)/(2mol Mg) to get 0.0829mol O₂.  From here you would usually use PV=nRT and solve for V However, the question tells us that we are at STP, that means you can use the fact that 22.4L of gas is 1 mol of gas at STP.  Using that information we can find the volume of O₂ gas by mulitlying 0.0829mol O₂ by 22.4L/mol to get 1.857L which equals 1857mL.
therefore, 1857mL of O₂ gas will react with 4.03g of Mg.

I hope this helps. Let me know in the comments if anything is unclear.
6 0
3 years ago
Read 2 more answers
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