<span>After alcohol is metabolized in the liver, it is burned as fuel for the cells. </span>
Answer:
Ytterbium is a chemical element with the symbol Yb and atomic number 70. It is the fourteenth and penultimate element in the lanthanide
Answer:
2-ethoxy-2-methylpropan-1-ol
Explanation:
On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid 
). The acid medium will produce the <u>hydronium ion</u> (
). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.
See figure 1
I hope it helps!
<h2>Let us predict the gas and liquid products in option </h2>
Explanation:
option 1 : 2 upper H g upper O (s) right arrow 2 upper H g (l) plus upper O subscript 2 (g).
Chemical reaction
It is the reactants react to form products .
Chemical equation
It is the method of representing reaction in terms of moles , specifying states , symbols , molecular formulas etc .
This actually gives the complete info about the reaction .
In the above asked question or any other question we can specify the states by writting :
Solid as "S".
Liquid as "L"
Gas as (g).
A) sodium fluoride
B) rubidium oxide
C) boron trichloride
D) dihydrogen selenide
E) tetraphosphate hexoxide
F) iodine trichloride
