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Assoli18 [71]
3 years ago
7

Quadrilateral ABCD with vertices A(-9, 2), B(-8, 8), C(-4, 6), and D(-2, 2) is shown. You want to reflect quadrilateral ABCD in

the
vertical line that passes through the midpoint of BC . Graph the line of reflection and the image after the reflection.
Mathematics
1 answer:
telo118 [61]3 years ago
7 0

Answer:

See explanation.

Step-by-step explanation:

Graph the quadrilateral. By inspection, you can tell where the midpoint is. (see attachment 1)

Now, I'll draw a line through it. (see attachment 2)

To reflect across a line, think about the points traveling across the line the same number of spaces the point is from the line. For example, point A is three away from the line. So, A' will be 3 away from the other side. The coordinates will be at (-3,2). (see attachment 3).

Do the same for the other points, and you'll have your image.

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3. x + 4y = 30<br> x - 2y = 0
kolbaska11 [484]

Answer:

Step-by-step explanation:

Given that:

x + 4y = 30

x - 2y = 0

Subtracting both equations:

6y = 30

y = 30/6

y = 5

Putting in above equation

x + 4(5) = 30

x + 20 = 30

x = 10

i hope it will help you

5 0
3 years ago
Hannah notices that segment HI and segment KL are congruent in the image below: Two triangles are shown, GHI and JKL. G is at ne
BlackZzzverrR [31]

Answer:

segment IG ≅ segment LJ

Step-by-step explanation:

Please refer to the attached image as per the triangles as given in the question statement.

\triangle HGI, \triangle JKL

G\left(-3,1\right),\ H\left(-1,1\right),\ I\left(-2,3\right)

J\left(3,3\right),K\left(1,3\right),L\left(2,1\right)

Given that:

HI\cong KL and

\angle I \cong \angle L

<em>SAS congruence </em>between two triangles states that two triangles are congruent if two corresponding sides and the angle between the two sides are congruent.

We are given that one angle and one sides are congruent in the given triangles.

We need to prove that other sides that makes this angle are also congruent.

To show the triangles are congruent i.e. \triangle GHI \cong \triangle JKL by SAS congruence we need to prove that

segment IG ≅ segment LJ

Let us use Distance formula  to find IG and LJ:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

IG  =\sqrt{(-2+3)^2+(3-1)^2} =\sqrt5\ units

LJ  =\sqrt{(2-3)^2+(1-3)^2} =\sqrt5\ units

Hence, segment IG ≅ segment LJ

\therefore ΔGHI ≅ ΔJKL by SAS

4 0
3 years ago
1.
olchik [2.2K]

Answer:

I got B

Step-by-step explanation

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60 is 3/8 of what number
OlgaM077 [116]
<span>60 is 3/8 of the number 160</span>
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