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TiliK225 [7]
3 years ago
13

The Tevatron accelerator at Fermilab (Illinois) is designed to carry an 11 mA beam of protons traveling at very nearly the speed

of light (300,000,000 m/s) around a ring 6300 m in circumference. How many protons are stored in the beam
Physics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

The number  is  N= 1.442*10^{12} \ protons

Explanation:

From then question we are told that

   The current carried is I_p = 11mA =11 *10^{-3}A

    The speed is c = 3.0*10^8 m/s

    The circumference is D = 6300 \ m

Mathematically current is expressed as

                 I = \frac{Q}{t} where Q is the quantity of charge passing through a conductor and t is the time in seconds

 The time t can be mathematically represented as

                 t = \frac{D}{ c}

Substituting this into the equation fro current

                 I = \frac{Q}{\frac{D}{c} }

Now making the quantity of charge the subject of the formula

            Q = \frac{I *  D}{c}

Generally the number of proton in the beam is mathematically represented as  

            N = \frac{Q}{n}

Where n is the charge on one proton with a value of n= 1.602*10^{-19}C

Now substituting for q in the equation for N

             N = \frac{I * D}{c * n}

Substituting values

            N = \frac{11*10^{-3} * 6300}{ 3.0*10^8 * 1.602 *10^{-19}}

                N= 1.442*10^{12} \ protons

     

     

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