3 years ago

How to write 310,763,136 in expanded form

Chemistry

2 answers:

andreyandreev [35.5K]3 years ago

8 0

Answer:

Explanation:

"Three hundred ten million, seven hundred sixty-three thousand, one hundred thirty-six".

Marizza181 [45]3 years ago

4 0

Answer:"Three hundred ten million, seven hundred sixty-three thousand, one hundred thirty-six".

Explanation:

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nikitadnepr [17]

Because diffusion<span> is the process when molecules move to lower or higher concentration, so as the molecules move faster they are going to lower or high concentration faster.</span>

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Which of the following is NOT an example of covalent bonding? * 2 points H20 NaF NH3 O2

Pachacha [2.7K]

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A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$