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marta [7]
3 years ago
9

Teresa has taken three tests worth 100 points each. Her scores are 85, 93, and 88. She has one test left to take.

Chemistry
1 answer:
Law Incorporation [45]3 years ago
5 0

Answer:

SOrry it makes me writer sotufjksankdn

Explanation:

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HELP HELP PLS !! <br> 5N<br> 21N
Sonja [21]

Answer:

Check the image file attached

Explanation:

6 0
3 years ago
Which pair of elements are in the same period?Hg &amp; PbLi &amp; NaB &amp; ClO &amp; As
Alexeev081 [22]

Answer:

Hg Pb are in one, Li and B and O are in one, and NaCl are in one, As is alone

Explanation:

Periods are horizontal

Hope this helps!

4 0
2 years ago
What is the oxidation number of sulfur in H2SO3?<br> a. +3<br> b. +1<br> c. +2<br> d. +4
Alla [95]
We need to keep in mind that the compound is neutral.

H2SO3
2(+1)+S+3(-2)=0 (since its neutral)
2+S-6=0
S-4=0
S=4

Therefore the oxidation number for sulfur is +4.
3 0
3 years ago
Read 2 more answers
An evil villain wants to broadcast a message to everyone on Earth. They are using satellites for the communication process. For
stira [4]
Uhhhhhhh maybe the answer is 3
7 0
2 years ago
Determine the equilibrium constant, Kp, for the following reaction, by using the two reference equations below: 2 NO(g) + O2(g)
klio [65]

Answer:

Kp=3.07x10^6

Explanation:

Hello,

In this case, by knowing the given reference reactions, one could rearrange them as follows:

2 NO(g) \leftrightarrow N_2(g) + O_2(g); Kp_2 = \frac{1}{2.3 x 10^{-19}}=4.35x10^{18}

N_2(g) + 2O_2(g) \leftrightarrow 2NO_2(g);Kp_3=(8.4x10^{-7})^2=7.056x10^{-13}

Subsequently, to obtain the main reaction, we add the aforementioned reference rearranged reactions as shown below (just as reference):

2NO(g)+N_2(g)+2O_2\leftrightarrow 2NO_2(g)+N_2+O_2

Consequently, the equilibrium constant is computed as:

Kp=\frac{[N_2][O_2]}{[NO]^2} * \frac{[NO_2]^2}{[N_2][O_2]^2} =Kp_2*Kp_3=4.35x10^{18}*7.056x10^{-13}=3.07x10^6

Best regards.

8 0
3 years ago
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