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Nata [24]
2 years ago
5

You heat up a 3.0 kg aluminum pot with 1.5 kg of water from 5 to 90o Celsius. The specific heat capacity of Aluminum is 900 J/kg

K. (a) How much energy did it take to heat the pot of water
Physics
1 answer:
Evgen [1.6K]2 years ago
8 0

Answer:

<em>765,000Joules or 765kJ</em>

Explanation:

The Quantity of heat required is expressed as;

Q = (mcΔt)al + (mcΔt)water

m is the mass

c is specific heat capacity

Δt is the change in temperature

Q = (3(900)(90-5)) + (1.5(4200)(90-5))

Q = 2700*85 + 6300*85

Q = (2700+6300)85

Q = 9000*85

<em>Q = 765,000</em>

<em>Hence the amount of energy needed is 765,000Joules or 765kJ</em>

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