The Ammonia present in 2.5 mole of Ammonia is 42.5grams.
<h3>What is a mole ?</h3>
A mole is a measuring unit in Chemistry to measure the number of atoms in certain molar mass of a substance.
It is given that 2.5 mole of Ammonia is present
Grams of Ammonia present in 2.5 mole of Ammonia = ?
Molecular weight of Ammonia = 17 grams.
1 mole of Ammonia = 17 grams of Ammonia
2.5 mole of Ammonia = 17 * 2.5
= 42.5 grams
Therefore 42.5 grams of Ammonia is present in 2.5 mole of Ammonia.
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Answer:
Explanation:
Given that:
The heat of combustion of methylhydrazine =
It means that:
1 mole of methylhydrazine on combustion, releases of energy
Molar mass of methylhydrazine = 46.072 g/mol
Means that, 1 mole of methylhydrazine contains 46.072 g of methylhydrazine
Thus,
46.072 g of methylhydrazine on combustion, releases of energy
Also,
1 g of methylhydrazine on combustion, releases of energy
206.2 g of methylhydrazine on combustion, releases of energy
Heat released =
this is true that compounds are made up of more than one type of element bound together in fixed ratios
because compound is a mixture of two or more elements in a ratio
Carbohydrates, proteins and fats are biological macro molecules that are made up of chemical elements which are inherent to chemistry.
Chemistry explain how these macro molecules are bonded together at the molecular level and give explanation for their behavior.