85 comes immediately before
RemarkIf you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step OneDivide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step TwoDifferentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =
Frankly I like the first answer better, but you have a choice of both.
Answer:
2(x + 2)² - 5
Step-by-step explanation:
Given
2x² + 8x + 3
To obtain the required form use the method of completing the square.
The coefficient of the x² term must be 1, thus factor 2 out of 2x² + 8x
= 2(x² + 4x) + 3
add/subtract ( half the coefficient of the x- term)² to x² + 4x
= 2(x² + 2(2)x + 4 - 4) + 3
= 2(x + 2)² - 8 + 3
= 2(x + 2)² - 5
with p = 2 and q = - 5
The answer is 9. there are 9 different combinations to choose from.
Answer:
2.4
Step-by-step explanation: