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garri49 [273]
3 years ago
5

What did most of the particles that Rutherford shot at the gold foil do? What was the surprising behavior of a few of the partic

les? What did he determine?
Chemistry
1 answer:
Masja [62]3 years ago
6 0

Answer:

Explanation:

Rutherford gold experiment gave the explanation to some observations made on atoms.

When he shot the gold foil, most of the \alpha-particles passes through the foil undeflected nor absorbed. This faction of the particles propagated the foil as if there was nothing placed on their path.

The surprising behavior of a few of the \alpha-particles was that they were deflected from their initial path on hitting the gold foil.

This implies that there is a part of the gold foil which has the same charge as the \alpha-particles, and more massive than the particles. Thus, he was able to determine the nucleus of an atom.

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During an experiment, Jasmine observes light being produced from mixing 2 substances in a beaker. What does this evidence sugges
Lubov Fominskaja [6]

Answer: C. A Chemical Change

Explanation:

A chemical change is one that occurs when new substances are produced preceding a chemical reaction ( the  mixing  or combination of one substance  with another).

From the experiment by Jasmine, since light was produced from the mixture,  energy is being released which is due to a  chemical change.

4 0
3 years ago
½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole 21.0 kcal/mole + C(s) + 2S(s) → CS2(l) What type of reaction is represented by the
wlad13 [49]

<u>Answer:</u>

Exothermic Reaction are those reaction, in which energy is released while in endothermic reaction are those, in which energy is absorbed.

<u>Explanation:</u>

First Reaction:

As in this reaction, energy is released

½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole

so it is <em>exothermic reaction</em>

Second reaction:

As in this reaction, energy is absorbed

21.0 kcal/mole + C(s) + 2S(s) → CS2(l)

so it is <em>endothermic reactions</em>.


7 0
4 years ago
Read 2 more answers
Heat transfer between two substances is affected by specific heat and the chemical composition of the substances. state of matte
lesya [120]

Answer:

the answer is D

Explanation:

7 0
3 years ago
Read 2 more answers
The structural level of a protein least affected by a disruption in hydrogen bonding is the
sergeinik [125]
I think the correct answer from the choices listed above is option A. The structural level of a protein least affected by a disruption in hydrogen bonding is the primary level. The other levels are very much affected by hydrogen bonding. Hope this answers the question.
7 0
4 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
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