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just olya [345]
3 years ago
5

The half-life of 131I is 8.021 days.What fraction of a sample of 131I remains after 24.063 days

Chemistry
1 answer:
Leno4ka [110]3 years ago
5 0
24.063/8.021 = 3 half lives
(1/2)^3 =1/8 
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Which of these space missions visited the moon several times?
sesenic [268]

Answer:

Voyager 1

Explanation:

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3 0
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If the rate law for a reaction A → P is rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122 M, calcula
DedPeter [7]

Rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122M.

A rate law indicates the rate of a chemical response depends on reactant concentration. For a response inclusive of the price regulation commonly has the form rate = ok[A]ⁿ, in which okay is a proportionality constant known as the fee regular and n is the order.

The charge of a chemical response is, perhaps, its maximum crucial asset because it dictates whether or not a reaction can arise all throughout an entire life. knowing the charge regulation, an expression concerning the price to the concentrations of reactants can assist a chemist to modify the response conditions to get an extra suitable rate.

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3 0
2 years ago
PLSSS HELP FAST
Aliun [14]

Note the formula

\boxed{\sf Mass\:no=No\:of\:protons+No\:of\:neutrons}

For X:-

  • No of protons:-

\\ \sf\longmapsto 19-10=9protons

  • It is Fluorine.

For Y:-

  • No of protons:-

\\ \sf\longmapsto 16-8=8protons

  • It is Oxygen.

Option D is correct

7 0
2 years ago
You bought a new fish aquarium with the dimensions of 55 cm x 100 cm x 80 cm. what volume of water should you put in it? Show yo
harina [27]
Since its volume you do what it says 55 cm x 100 cm x 80cm and do 100 x 50 which is 5,000. then 5,000 x 80 which is 40,000. sorry i cant show work on here.
8 0
4 years ago
C). If 0.5 mole of oxygen (,) reacted with hydrogen (H2), how many mole of water (H20) was produced
son4ous [18]

Answer:

1 mol of water is produced in those conditions.

Explanation:

The reaction to produce water between H₂ and O₂ is this:

2H₂  +  O₂  →  2H₂O

We don't have the amount of hydrogen, so we have to think that is in excess.

Let's work with oxygen.

Ratio is 1:2

For 0.5 mole of oxygen, I will make the double of moles of water.

4 0
3 years ago
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