If 1mol ------- is ----------- 6,02×10²³
so x ------- is ----------- 1,39×10²⁴
so x ------- is ----------- 1,39×10²⁴
The half-life of 131I is 8.021 days.What fraction of a sample of 131I remains after 24.063 days
1 answer:
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Answer:The volume of the remaining gas that is ammonia is 23.85 L.
Explanation:
Moles of
Moles of HCl of gas =
According to reaction 1 mole of HCl reacts with 1 mol of then 2.06 moles of HCl will react with = 2.06 moles of
Moles left of ammonia left = 4.43 - 2.06 = 2.36 moles
Volume of the gas will be given by Ideal gas equation: PV=nRT
Pressure = 752 mmHg = 752 × 0.0031 atm = 2.33 atm
R = 0.08026 L atm/K mol
V = ? , n = number of moles of ammonia
Temperature = 14 °C = 14 + 273 K = 287 K(0°C = 273K)
The volume of the remaining gas that is ammonia is 23.85 L.
Answer:
The percent yield of chloro-ethane in the reaction is 82.98%.
Explanation:
Moles of ethane =
Moles of chlorine gases =
As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.
This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.
According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.
Then 9.1549 moles of chlorien gas will give:
of chloro-ethane
Mass of 9.1549 moles of chloro-ethane:
9.1549 mol × 64.5 g/mol = 590.4910 g
Theoretical yield of chloro-ethane: 590.4910 g
Given experimental yield of chloro-ethane: 490.0 g
The percent yield of chloro-ethane in the reaction is 82.98%.
Above question is incomplete. Complete question is attached below
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Correct Answer: Option D i.e. CH3CH2CH2CH2CH3
Reason:
Isomers are the compounds having same molecular formula, but different structural formula.
The molecular formula of the compound is C5H12
The compound present is question (i.e. 2-methyl butane) and option D (n-pentane) has same molecular formula. Hence, they are isomers.
However, compound present in option A, is the same compound provided in question. Hence, it is not an isomer. Compounds reported in option B and C has one carbon atom less and more, respectively as compared to the compound reported in question. Hence, they are also not isomers.
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Correct Answer: Option D i.e. CH3CH2CH2CH2CH3
Reason:
Isomers are the compounds having same molecular formula, but different structural formula.
The molecular formula of the compound is C5H12
The compound present is question (i.e. 2-methyl butane) and option D (n-pentane) has same molecular formula. Hence, they are isomers.
However, compound present in option A, is the same compound provided in question. Hence, it is not an isomer. Compounds reported in option B and C has one carbon atom less and more, respectively as compared to the compound reported in question. Hence, they are also not isomers.