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Mice21 [21]
3 years ago
10

These allow electricity to flow easily through them (think copper and aluminum).

Chemistry
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

conductors

Explanation:

You might be interested in
What type of substances does conduction work best in? in other words what substances are good conductors?
vaieri [72.5K]

Explanation:

Electric conductors are the substances which allow easy passage of electric charges from one atom to another in the presence of a certain amount of voltage.

A conductor in which electric charge passes easily is known as a good conductor. Whereas a conductor in which electric charge passes with difficulty or no electric charge passes through is known as bad conductor.

For example, copper is good conductor of heat and electricity as it conducts flow of current quite easily.

3 0
4 years ago
A volume of 60.0 mL of a 0.120 M HNO3 solution is titrated with 0.840 M KOH. Calculate the volume of KOH required to reach the e
german

Answer: 8.57 ml of KOH is required to reach the equivalence point.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.120M\\V_1=60.0mL\\n_2=1\\M_2=0.840M\\V_2=?

Putting values in above equation, we get:

1\times 0.120\times 60.0=1\times 0.840\times V_2\\\\V_2=8.57mL

Thus 8.57 ml of KOH is required to reach the equivalence point.

8 0
4 years ago
1) 2C2H6 + 7O2 --> 4CO2 + 6H2O
Lena [83]

Answer:

a).

2 \: moles \: of \: ethane \: react \: with \: 7 \: moles \: of \: oxygen \\ 24 \: moles \: react \: with \: ( \frac{24 \times 7}{2} ) \: moles \\  = 84 \: moles

b).

2 \: moles \: react \: with \: 7 \: moles \\ ( \frac{12 \times 2}{7} ) \: moles \: react \: with \: 12 \: moles \\  = 3 .43 \: moles \\ 1 \: mole \: weighs \: 30 \: g \\ 3.43 \: moles \: weigh \: (3.43 \times 30) \\  = 102.9 \: g

c).

746.7 g

7 0
3 years ago
Complete the passage about metallic bonding.
Burka [1]

Answer:

some bonds are broken and new ones are formed. Now you are ready to learn more about those bonds. Chemical bonds are attractions between atoms. They are simply attractive forces (between the + nucleus of one atom and the - electrons of a neighboring atom) that hold groups of atoms together and make them function as a unit.

7 0
3 years ago
Determine the change in entropy for 2.7 moles of an ideal gas originally placed in a container with a volume of 4.0 L when the c
olchik [2.2K]

Answer:

The value of entropy change for the process dS = 0.009 \frac{KJ}{K}

Explanation:

Mass of the ideal gas = 0.0027 kilo mol

Initial volume V_{1} = 4 L

Final volume V_{2} = 6 L

Gas constant for this ideal gas ( R ) = R_{u}  M

Where R_{u} = Universal gas constant = 8.314 \frac{KJ}{Kmol K}

⇒ Gas constant R = 8.314 × 0.0027 = 0.0224 \frac{KJ}{K}

Entropy change at constant temperature is given by,

dS = R  log _{e} \frac{V_{2}}{V_{1}}

Put all the values in above formula we get,

dS = 0.0224  log _{e} [\frac{6}{4}]

dS = 0.009 \frac{KJ}{K}

This is the value of entropy change for the process.

6 0
3 years ago
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