CH3CH2OH = 46.068 (molar mass)
1.50g(1 mole / 46.0680) =
0.03256 moles
Explanation:
b I dont really know okau
Answer:
ΔT = 0.78 °C
Explanation:
Given data:
Mass of Al = 9.5 g
Specific heat capacity of Al = 0.9 J/g.°C
Temperature change = ?
Heat added = 67 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
67 J = 9.5 g × 0.9 j/g.°C × ΔT
67 J = 85.5 j/°C × ΔT
ΔT = 67 J / 85.5 j/°C
ΔT = 0.78 °C
*Go into solution
*Break down
*Liquefy
*Disintegrate
*Melt away
*Evaporate
*Dissapear
Hope it helps! Brainliest answer, PLZ? :)
The more particles (ions or molecules) that you can put into solution, the lower the freezing point.
the answer is E. 2.0 M nacl
