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3 years ago

Which is an important question to consider when creating an environmental policy?

Chemistry

2 answers:

Vinvika [58]3 years ago

6 0

Answer:

Is The Benefit Worth The Cost?

Explanation:

morpeh [17]3 years ago

4 0

Answer: is the benefit worth the cost?

Explanation: for those on edge :)

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Please help!! A lot of points!!

Artist 52 [7]

Mean: the average. you have to add the values of the numbers and then divide by the amount of numbers there are. a common mistake to avoid is forgetting to divide the numbers at the end or subtracting them instead of adding.

mean: the middle number. you would first need to order the numbers from least to greatest. a common mistake to avoid is finding the middle number before ordering it from least to greatest

these two can also be commonly mistaken for one another because of the similar spelling.

7 0

3 years ago

Which of the following compounds will undergo an Sn2 reaction most readily?

Bad White [126]

Answer:

nekwkz8 waxed

Explanation:

snswko1u219ux8w ok qqm see

4 0

2 years ago

A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?

horsena [70]

Answer: The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

Explanation:

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL$

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = $\frac{44g}{77.46mL}\times 60mL=34.1g$

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0

3 years ago

Which statement is true about Air at different temperatures

Alchen [17]

Are there any choices?

6 0

3 years ago

Read 2 more answers

Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.

Akimi4 [234]

Answer is: the empirical formula of the hydrocarbon is CH₂.
Chemical reaction: CₓHₐ + O₂ → xC + a/2H₂O.
m(CO₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.

6 0

3 years ago