3 years ago

A bike travels at 3.0 m/s, and then accelerates to a speed of

Physics

1 answer:

suter [353]3 years ago

7 0

Answer:

2.2m/s²

Explanation

Initial velocity of bike = 3m/s

Final velocity of bike = 8.5m/s

Total time = 2.5 seconds

Acceleration = (Final velocity - initial velocity) / time

= 8.5 - 3 / 2.5

= 5.5/2.5 => 2.2 m/s²

You might be interested in

What must happen to the electrons in a material to create an electric current?

bezimeni [28]

They have to have a positive charge and negative so then thats what u get

6 0

3 years ago

Maganda ka Tapos Liit mopa<br>

kirza4 [7]

Answer:

naol may pinoy dito nag jakoI

5 0

3 years ago

What's effect called?<br>

k0ka [10]

Answer:

what do u mean

Explanation:

8 0

3 years ago

Read 2 more answers

Question 25 of 30

VARVARA [1.3K]

Answer:

it's B. circuit a and b are series circuit while c is parallel

7 0

3 years ago

A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh

DiKsa [7]

Answer:(a)360N,(b)171N,(c)2.702m

Explanation:

(a)Maximum Friction Force = $\mu \left ( N\right )=0.4\times \left ( 740+160\right )$

=360 N

$cos\theta =\frac{3}{5}$

$sin\theta =\frac{4}{5}$

(b)Moment about Ground Point

$740\times 1\times cos\theta +2.5\times 160\times cos\theta -N_15sin\theta$

$N_1tan\theta =1140$

$N_1=171 N$

$N_1=f=171 N$

(c)

$740\times x\times cos\theta +2.5\times 160\times cos\theta -N_15sin\theta$

Here maximum friction force can be 360 N

Therefore $N_1=360 N$

Where x is the maximum distance moved by man along the ladder

$360\times 5\times \frac{4}{3}=740x+160\times 2.5$

740x=2000

x=2.702m

5 0

3 years ago