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3 years ago

A bike travels at 3.0 m/s, and then accelerates to a speed of

Physics

1 answer:

suter [353]3 years ago

7 0

Answer:

2.2m/s²

Explanation

Initial velocity of bike = 3m/s

Final velocity of bike = 8.5m/s

Total time = 2.5 seconds

Acceleration = (Final velocity - initial velocity) / time

= 8.5 - 3 / 2.5

= 5.5/2.5 => 2.2 m/s²

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Sarah, whose mass is 40 kg, is on her way to school after a winter storm when she accidentally slips on a patch of ice whose coe

RideAnS [48]

Sarah's acceleration is $-0.49 m/s^2$

Explanation:

The force of kinetic friction acting on Sarah has a magnitude which is given by:

$F_f = \mu mg$

where

$\mu$ is the coefficient of kinetic friction

m is Sarah's mass

g is the acceleration of gravity

Moreover, according to Newton's second law of motion, we know that the net force on Sarah is equal to its mass times its acceleration:

$F=ma$

where a is the acceleration

Since the force of friction is the only force acting on Sarah, we can say that the net force is equal to the force of friction, therefore:

$F=-\mu mg = ma$

where the negative sign is due to the fact that the force of friction has a direction opposite to the motion of Sarah. Solving for a, we find

$a=-\mu g$

And substituting the following values:

$\mu = 0.05$ (coefficient of friction)

$g=9.81 m/s^2$ (acceleration of gravity)

we find:

$a=-(0.05)(9.81)=-0.49 m/s^2$

Learn more about acceleration and forces:

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4 0

3 years ago

Through what potential difference would you need to accelerate an alpha particle, starting from rest, so that it will just reach

Svetlanka [38]

Answer:

$\Delta V = 1.8 \times 10^7 V$

Explanation:

GIVEN

diameter = 15 fm = $15 \times 10^{-15}$ m

we use here energy conservation

$K_{i}+U_{i} =K_{f}+U_{f}$

there will be some initial kinetic energy but after collision kinetic energy will zero

$K_{i} + 0 = 0 + \frac{1}{4 \pi \epsilon _{0}} \frac{(2e)(92e)}{7.5 \times 10^{-15}}$

on solving these equations we get kinetic energy initial

$KE_{i} = 5.65\times 10 ^{-12} \times \frac {1 eV}{1.6 \times 10^{-19}}$

$KE_{i} = 35.33$ J ..............(i)

That is, the alpha particle must be fired with 35.33 MeV of kinetic energy. An alpha particle with charge q = 2 e

and gains kinetic energy K =e∆V ..........(ii)

by accelerating through a potential difference ∆V

Thus the alpha particle will

just reach the ${238}_U$ nucleus after being accelerated through a potential difference ∆V

equating (i) and second equation we get

e∆V = 35.33 Me V

$\Delta V = \frac{35.33}{2} MV\\\Delta V = 1.8 \times 10^7 V$

7 0

3 years ago

If the electric field of an electromagnetic wave is in the x-direction and the magnetic field of the wave is in the y-direction,

Ulleksa [173]

Answer:

Positive z-direction

Explanation:

According to Fleming's right hand rule, point the fingers of your right hand in the direction of Electric field E ( positive x-direction), and curl your fingers toward magnetic field B (positive y-direction), and your thumb points in the direction of propagation of wave (positive z-direction).

Therefore, the correct option will be positive z-direction.

3 0

3 years ago

A wildebeest runs with an average speed of

vagabundo [1.1K]

How many seconds did the wildebeest run??

4 0

3 years ago

Technician A says that module communications networks are used to reduce the number of wires in a vehicle. Technician B says tha

Flauer [41]

Answer:

c) both technician A and B

Explanation:

A communication network is a collection of the interconnected networks that are managed to support the transfer of the information form a user in one network location and to a user of the another node.

Are connected as the link and to enable the communication and sharing of the data between the terminals and different modules. Hence both the A and B technicians are equally correct.

5 0

3 years ago