Answer:
Most of the frogs have webbed feet which helps them swim. The thin skin between the toes helps them to push through the water. The frog's feet is webbed ,So they can easily swim.. The skin between toes are flexible soo they can freely push and pull it
Explanation:
Answer:
e) 11 m/s
Explanation:
For a particle under the action of a conservative force, its mechanical energy at point 0 is must be equal to its mechanical energy at point 1:
![K_1+U_1=K_0+U_0\\\\\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(x_1)^2+(2.0\frac{J}{m^4})(x_1)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})(x_0)^2+(2.0\frac{J}{m^4})(x_0)^4]](https://tex.z-dn.net/?f=K_1%2BU_1%3DK_0%2BU_0%5C%5C%5C%5C%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%29%28x_1%29%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%28x_1%29%5E4%5D%3D%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%29%28x_0%29%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%28x_0%29%5E4%5D)
In 
the speed is given, so 
and 
. Replacing:
![\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(1m)^2+(2.0\frac{J}{m^4})(1m)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})0^2+(2.0\frac{J}{m^4})(0)^4]\\\frac{mv_1^2}{2}+8.0J+2.0J=\frac{mv_0^2}{2}\\\frac{mv_0^2}{2}=\frac{mv_1^2}{2}+10J\\v_0=\sqrt{\frac{2}{m}(\frac{mv_1^2}{2}+10J)}\\v_0=\sqrt{\frac{2}{0.2kg}(\frac{(0.2kg)(5\frac{m}{s})^2}{2}+10J)}\\v_0=11.18\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%29%281m%29%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%281m%29%5E4%5D%3D%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%290%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%280%29%5E4%5D%5C%5C%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B8.0J%2B2.0J%3D%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%5C%5C%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%3D%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B10J%5C%5Cv_0%3D%5Csqrt%7B%5Cfrac%7B2%7D%7Bm%7D%28%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B10J%29%7D%5C%5Cv_0%3D%5Csqrt%7B%5Cfrac%7B2%7D%7B0.2kg%7D%28%5Cfrac%7B%280.2kg%29%285%5Cfrac%7Bm%7D%7Bs%7D%29%5E2%7D%7B2%7D%2B10J%29%7D%5C%5Cv_0%3D11.18%5Cfrac%7Bm%7D%7Bs%7D)
The greenhouse gases absorb some of this energy and radiate much of it back towards the surface whilst the rest is radiated out to space. This plays an important role in keeping the Earth's surface warm and able to sustain life.
Answer:
1.a) 1 kJ
1.b) 4 kJ
ratio 1:4
1.c) 4 times as before
2.a) 3.33 m/s2
Explanation:
1.a) bicycle's velocity =Displacement/time
=100/20 m/s
=5 m/s
bicycler's KE =1/2 *mass*(velocity)^2
=1/2*80*5^2
=1000 J = 1 kJ
1.b) bicycle's new velocity =200/20 m/s
=10 m/s
bicycler's new KE =1/2*80*10^2
=4000 J = 4 kJ
Ratio= KE 1 :KE new
= 1 :4
1.c) when bicycler's speed was doubled it increased the KE by 4 times (2^2). because In KE we consider the square of the speed , so the factor we increase the speed , the KE will get increased with the square value of it
ex : speed is triple the prior value , then the KE is as 3^2 times as before. that is 9 times
2.a) car acceleration = (20-0)/6 m/s2
= 3.33 m/s2
