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nekit [7.7K]
3 years ago
12

What are the values of m and 0 in the diagram below?

Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

<h3>The correct answer is</h3>

hope it helps

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What is the ratio of red to blue squares in its simplest form?<br> 14 red 4 blue
zlopas [31]

Simplest Form: 7 : 2

How to Simplify a Ratio A : B when A and B are both whole numbers:

  1. List the factors of A
  2. List the factors of B
  3. Find the greatest common factor of A and B, GCF(A, B)
  4. Divide A and B each by the GCF
  5. Use the whole number results to rewrite the ratio in simplest form

Try to reduce the ratio further with the greatest common factor (GCF).

<em>The GCF of 14 and 4 is 2</em>

Divide both terms by the GCF, 2:

14 ÷ 2 = 7

4 ÷ 2 = 2

The ratio 14 : 4 can be reduced to lowest terms by dividing both terms by the GCF = 2 :

14 : 4 = 7 : 2

Therefore:

14 : 4 = 7 : 2

5 0
3 years ago
15) students in 7 classrooms.<br> per classroom
bogdanovich [222]

Answer:

105

Step-by-step explanation:

15x7

3 0
2 years ago
X over 3 - 2 = 5x - 2 , having trouble solving for x or x/3 -2 = 5x -2
Len [333]
I got x=0 because I simplified both sides of the equation and then isolated the equation
7 0
2 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
V=1/3Πr^2(2r+h)
stiv31 [10]

Answer:

h= \frac{−2.094395r3+v}{1.047198r2}

Step-by-step explanation:

v=(  \frac{1}{3} (3.141593))(r2)(2r+h)

Step 1: Flip the equation.

1.047198hr2+2.094395r3=v

Step 2: Add -2.094395r^3 to both sides.

1.047198hr2=−2.094395r3+v

Step 3: Divide both sides by 1.047198r^2.

h= \frac{−2.094395r3+v}{1.047198r2}

3 0
3 years ago
Read 2 more answers
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