Answer:
2F
Explanation:
Given;

G is is the universal gravitational constant. Since G is a constant, we could rewrite equation (1) as follows;

When one of the masses is altered, the force changes to a new value, say
.
In this case it is said that
is doubled.
Equation (2) therefore implies that we can write the following;

We are assuming that all other parameters a parts from
remain the same.
By appropriately cancelling out parameters from both side of the equation (3), we obtain the following;

The new gravitational force in terms of F is therefore'

Wave speed = (wavelength) x (frequency)
We know the wavelength, but we don't know the frequency. How can we find the frequency ? "Here frequency frequency."
We know the period, and frequency is just (1 / period). So . . .
Wave speed = (wavelength) / (period)
Wave speed = (2.1 meters) / (9.4 seconds)
Wave speed = (2.1 / 9.4) m/s
<em>Wave speed = 0.223 m/s</em>
Explanation:
<em>Here </em><em>it </em><em>is </em><em>given </em>
<em>Work </em><em>(</em><em>W) </em><em> </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em> </em><em>J</em>
<em>Time </em><em>(</em><em>t) </em><em> </em><em>=</em><em> </em><em>5</em><em>5</em><em> </em><em>sec</em>
<em>power </em><em>(</em><em>P) </em><em> </em><em>=</em><em> </em><em>?</em>
<em>We </em><em>know </em><em>we </em><em>have </em><em>the </em><em>formula </em>
<em>
</em>
<em>P </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em>/</em><em>5</em><em>5</em>
<em>P </em><em>=</em><em> </em><em>6</em><em>4</em><em>.</em><em>7</em><em>3</em><em> </em><em>watt</em>
I had to look for the other details and here is my answer:
The Becquerel's experiment was done by Henri Becquerel, a French physicist, who discovered radioactivity. In this experiment, what happens is that both (refers to uranium) created images when placed in their respective places. Neither created images when placed in their respective places.
Answer:
70db
Explanation:
If one typewriter 's sound recorded 60 dB, therefore 10 typewriters that clack away would register 70 dB (doesn't seem 600 dB!), but it would only sound double as loud as compared with one typewriter. You would gathers typesetters to strike a noise level of 80 dB and jointly they will only sound four times as loud as compared single typewriter.
So, it would be
= 20 + 50
= 70db