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krok68 [10]
2 years ago
8

Which term best describes the motion of the rope particles in relation to the motion of the rope wave shown in the photograph

Physics
2 answers:
Nady [450]2 years ago
3 0

Answer:

A: Perpendicular

Explanation:

The question is incomplete as it lacks the image of the rope wave motion.

However, as found on "estudyassistant", the options are;

A) Perpendicular

B) Circular

C) Longitudinal

D) Parallel

From all that, we can say that;

The rope's are moving simultaneously in the same pattern without touching each other.

This is therefore a mechanical wave being created with the motion having oscillations that are perpendicular to the direction of energy transfer of the ropes.

This is a definition of transverse waves because the rope particle motion is perpendicular to the wave motion.

Ivenika [448]2 years ago
3 0

Answer:

A: Perpendicular

Explanation:

Read above explanation.

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Vinil7 [7]
Water vapour has more kinetic energy.

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Which of the following would increase the elastic force acting on that object
olga_2 [115]

Answer:

Which of the following would increase the elastic force acting on that object? Moving a spring to an unstretched position. Compressing a spring twice as much as its starting position.

Explanation:

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A ball is launched from ground level at 20 m/s at an angle of 40° above the
DedPeter [7]

(a) The ball's height <em>y</em> at time <em>t</em> is given by

<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :

0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )

<em>t</em> = 0   or   (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 <em>g t</em>

<em>t</em> = (40 m/s) sin(40º) / <em>g</em>

<em>t</em> ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So

0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>

where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :

<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)

<em>y</em> ≈ 8.4 m

8 0
3 years ago
When you and a friend move a couch to another room you exert a force of 75 N over 5m how much work will you do
sesenic [268]

The work done is 375 J

Explanation:

The work done by a force in moving an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this problem,

F = 75 N is the force applied to the couch

d = 5 m is the displacement

Assuming the force applied to the couch is parallel to the motion, \theta=0

And so, the work done is

W=(75)(5)(cos 0)=375 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

6 0
3 years ago
I WILL GIVE BRAINLIST just please help with these problems 3
statuscvo [17]

Answer:

16. 68.18 Km/h

17. 3 miles.

Explanation:

16. Determination of the speed

Distance travelled = 150 Km

Time = 2.2 hours

Speed =?

Speed is simply defined as the distance travelled with time. Mathematically, it is expressed as:

Speed = Distance / time

With the above formula, we can obtain the speed as follow:

Distance travelled = 150 Km

Time = 2.2 hours

Speed =?

Speed = Distance /time

Speed = 150 / 2.2

Speed = 68.18 Km/h

17. Determination of the distance.

Speed = 3 mph

Time = 1 hour

Distance =?

Speed = Distance /time

3 = distance / 1

Distance = 3 miles

3 0
2 years ago
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