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antiseptic1488 [7]
2 years ago
5

What is wheel. and axle? Explain its structure with the help of a diagram​

Physics
1 answer:
nadya68 [22]2 years ago
4 0

Answer:

The wheel and axle consist of a round disk, known as a wheel, with a rod through the centre of it, known as the axle. This system uses angular momentum and torque to do work on objects, typically against the force of gravity. The wheel and axle simple machine is closely related to gears.

Explanation:

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Which of these objects must have the greatest force acting on it? pls help fast
8_murik_8 [283]

Let's look at Newton's second law

  • F=ma

Force is directly proportional towards mass

If mass is more force will be more.

Between baseball and bowling ball Bowling ball has higher mass

So it would expert most force

Option D

8 0
1 year ago
A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa
bearhunter [10]

Explanation:

Formula which holds true for a leans with radii R_{1} and R_{2} and index refraction n is given as follows.

          \frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

Since, the lens is immersed in liquid with index of refraction n_{1}. Therefore, focal length obeys the following.  

            \frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]  

             \frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

and,       \frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}

or,          f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}

              f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}

                          = 32.4 cm

Using thin lens equation, we will find the focal length as follows.

             \frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}

Hence, image distance can be calculated as follows.

       \frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}

              s_{i} = \frac{fs_{o}}{s_{o} - f}

             s_{i} = \frac{32.4 \times 100}{100 - 32.4}

                       = 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

4 0
3 years ago
A scientist heated a tank containing 50 g of water. The specific heat of water is 4.18 J/gºC. The temperature of the water incre
Amanda [17]
I got 5,225 by 50x4.18= 209(25)=5,225
6 0
2 years ago
1. What is the total distance traveled?<br> A 3.0m <br> B 4.0m <br> C 5.0m <br> D 6.0m
Ostrovityanka [42]

Answer:

c

Explanation:

7 0
2 years ago
A student places her 490 g physics book on a frictionless table. She pushes the book against a spring, compressing the spring by
Paul [167]

Answer:

book speed is 3.99 m/s

Explanation:

given data

mass m = 490 g = 0.490 kg

compressing x = 7.10 cm = 0.0710 m

spring constant k = 1550 N/m

to find out

book speed

solution

we know energy is conserve so

we can say

loss in spring energy is equal to gain in kinetic energy

so

\frac{1}{2}*k*x^2 = \frac{1}{2}*m*v^2    ..................1

put here value

\frac{1}{2}*1550*0.071^2 = \frac{1}{2}*0.490*v^2

v = 3.99 m/s

so book speed is 3.99 m/s

5 0
3 years ago
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