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musickatia [10]
3 years ago
9

An object has 100J of KE. It has a mass of 10kg. How fast is it travelling

Physics
1 answer:
MissTica3 years ago
4 0

k =  \frac{1}{2} mv {}^{2}
100 =  \frac{1}{2}  \times 10 \times v {}^{2}
100 = 5v {}^{2}
v {}^{2}  = 20
v =  \sqrt{20}  = 2 \sqrt{5}
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A solenoid 0.425 m long has 950 turns of wire. What is the magnetic field in the center of the solenoid when it carries a curren
lesya692 [45]

Answer:

The magnetic field in the center of the solenoid is 7.8\times10^{-3}\ T.

Explanation:

Given that,

Length of solenoid = 0.425 m

Number of turns N = 950

Current I = 2.75 A

The magnetic field in the center of the solenoid is the product of the current , number of turns per unit length and permeability.

In mathematical form,

B = \mu_{0}nI

Where, n = \dfrac{N}{l}

N = number of turns

L = length

I = current

Now, The magnetic field

B = \dfrac{\mu_{0}NI}{l}

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times950\times2.75}{0.425}

B=\dfrac{4\times3.14\times10^{-7}\times950\times2.75}{0.425}

B=7.8\times10^{-3}\ T

Hence, The magnetic field in the center of the solenoid is 7.8\times10^{-3}\ T.

4 0
3 years ago
Energy is to be stored in a flywheel in the shape of a uniform solid disk with a radius of R = 1.22 m and a mass of 67.0 kg . To
eduard

Answer: 71.7 KJ

Explanation:

The rotational kinetic energy of a rotating body can be written as follows:

Krot = ½ I ω2

Now, any point on the rim of the flywheel, is acted by a centripetal force, according to Newton’s 2nd Law, as follows:

Fc = m. ac

It can be showed that the centripetal acceleration, is related with the angular velocity and the radius, as follows:

ac =  ω2 r

We know that this acceleration has a limit value, so , we can take this limit to obtain a maximum value for the angular velocity also.

As the flywheel is a solid disk, the rotational inertia I is just ½ m r2.

Replacing in the expression for the Krot, we have:

Krot= ½ (1/2 mr2.ac/r) = ¼ mr ac = ¼ 67.0 Kg. 1.22 m . 3,510 m/s2 = 71. 7 KJ

5 0
2 years ago
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lidiya [134]

Answer:

Option D

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In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.  

In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.

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B: Energy lose

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