Following chemical reaction is involved upon titration of Ca(OH)2 with HCl,
Ca(OH)2 + 2HCl ↔ CaCL2 + 2H2O
Above is an example of acid-base titration to generate salt and water. Here, H+ ions of acid (HCl) combines with OH- (ions) of base [Ca(OH)2] to generated H2O
Given,
concentration of HCl = 0.0199 M
Total volume of HCl consumed during titration = 16.08 mL = 16.08 X 10^(-3) L
∴, number of moles of H+ consumed = Molarity X Vol. of HCl (in L)
= 0.0199 X 16.08 X 10^(-3)
= 3.1999 X 10^-4 mol
Thus, total number of moles of [OH-] ions present initial = 3.1999 X 10-4 mol
So, initial conc. [OH-] ion = ![\frac{number of moles of [OH-]}{volume of solution (L)}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bnumber%20of%20moles%20of%20%5BOH-%5D%7D%7Bvolume%20of%20solution%20%28L%29%7D%20)
=

= 0.03199 M
Answer:
It is a physical change because this change is reversible and no chemical reaction occurs.
Explanation:
We’d have to be very careful because if we had our skeletons on the outside it’d be very easy to injure ourselves
Answer:
Player B
Explanation:
I just did it and I got it right :)
Answer:
Mass of P4O6=103.4
P4O10=133.48
Explanation:
Balanced reaction is:
8P +8
⇒
+
Both reactant completely vanishes as equivalent of bot are equal.
Moles of P=
=3.80
Moles of
=
=3.80
No. of moles of formed product are equal and is
th of mole of any of reactant.
Thus weight of
=
×220 ≈103.41
weight of
=
×284 ≈133.48